Determine the empirical formula of a compound that has the following percent composition by mass: K 24.75 %, Mn 34.77 %, and O 40.51% (Solution) These mass abundances have to be converted to the counting units of mole to determine the empirical formula. 1 mol O 1 mol Mn 54.94 g Mn 1 mol K ng = 24.75 g K x nMn = 34.77 g Mn x no = 40.51 g O x- 39.10 g K 16.00 g O = 0.6330 molK = 0.6329 mol Mn = 2.532 mol O Ko.6330Mno.632902.532 Divide each number by the smallest number 0.6329 2.532 0.6330 K:0.6329 0.6329 x1.0 Mn: -= 1.0 0 * 4.0 · 0.6329 0.6329 KMNO4 QUESTION A sample of a compound containing boron (B) and hydrogen (H) contains 12.888 g of B and 3.606 g of H. Whatis the empirical formula of this compound? (the molar mass of B = 10.81 g; of H = 1.008 g) For your answer, type in the order of B and then H. Copyright © All Rights Reserved by M.Han

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Question
Determine the empirical formula of a compound that has the following percent composition by
mass: K 24.75 %, Mn 34.77 %, and O 40.51%
(Solution) These mass abundances have to be converted to the counting units of mole to
determine the empirical formula.
1 mol O
1 mol Mn
54.94 g Mn
1 mol K
nMn = 34.77 g Mn x
no = 40.51 g O x-
%3D
nk = 24.75 g K x
%3D
39.10 g K
16.00 g O
= 0.6329 mol Mn
= 2.532 mol O
= 0.6330 mol K
Ko.6330MN0.632902.532
Divide each number by
the smallest number 0.6329
0.6329
2.532
0.6330
K:
x1.0 Mn:
= 1.0 0
* 4.0
0.6329
0.6329
0.6329
KMNO4
QUESTION
A sample of a compound containing boron (B) and hydrogen (H) contains 12.888 g of B and 3.606 g of H.
What is the empirical formula of this compound? (the molar mass of B = 10.81 g; of H = 1.008 g)
For your answer, type in the order of B and then H.
Copyright © AllI Rights Reserved by M.Han
Transcribed Image Text:Determine the empirical formula of a compound that has the following percent composition by mass: K 24.75 %, Mn 34.77 %, and O 40.51% (Solution) These mass abundances have to be converted to the counting units of mole to determine the empirical formula. 1 mol O 1 mol Mn 54.94 g Mn 1 mol K nMn = 34.77 g Mn x no = 40.51 g O x- %3D nk = 24.75 g K x %3D 39.10 g K 16.00 g O = 0.6329 mol Mn = 2.532 mol O = 0.6330 mol K Ko.6330MN0.632902.532 Divide each number by the smallest number 0.6329 0.6329 2.532 0.6330 K: x1.0 Mn: = 1.0 0 * 4.0 0.6329 0.6329 0.6329 KMNO4 QUESTION A sample of a compound containing boron (B) and hydrogen (H) contains 12.888 g of B and 3.606 g of H. What is the empirical formula of this compound? (the molar mass of B = 10.81 g; of H = 1.008 g) For your answer, type in the order of B and then H. Copyright © AllI Rights Reserved by M.Han
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