Determine the electric potential at the midpoint between two protons that are held at rest with a distance of 969 nm between them. Then, calculate the electric field magnitude and direction at the same location. potential: V magnitude of field: N/C Direction of field:
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- detailsTwo point charges Q1 -80.0 µC and Q2 20.0 µC are separated by a distance d1 = 10.0 cm, as shown in the image. Calculate the potential at point A positioned d2 = 4.00 cm to the left of Q1. АAn electron is moved from point A to point B in a uniform electric field and gains 3.06x10- J of electrostatic potential 15 energy. Calculate the magnitude of the electrostatic potential difference between the two points.
- A -15 nC charge and a 9 nC charge are located on the x-axis at x=-6 cm and x=9 cm respectively. iii.How far to the left of the -15nC charge does the electric potential equal -27V? iv.What is the magnitude (in N/C) of the electric field at this location?Four point charges q1 = 2.222µC, q2 = -0.719µC, q3 = 6.687µC, and q4 = -2µC are located at the corners of a square whose side s = 0.315m. The potential (in J/C) at the center of square is...?Two protons are maintained at a separation of 877 nm. Calculate the electric potential due to the two particles at the midpoint between them. Then, find the magnitude and direction of the electric field there. potential: magnitude of field: The direction of field is toward one of the protons. another direction. undetermined. V N/C