Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to pointsDistance. The calculation is:Distance = √(x2 − x1)² + (y2 − y1)²Ex: For points (1.0, 2.0) and (1.0, 5.0), pointsDistance is 3.0.493714.3402758.qp3zqy71 #include 2 #include 3 using namespace std;456789101112131415161718192021int main() {double x1:double y1:double x2:double y2:double xDist;double yDist;double pointsDistance:xDist = 0.0;yDist = 0.0;pointsDistance = 0.0;cin >> x1;cin >> y1;cin >> x2;in17- &N&CNNNNE2122cin >> y2:/* Your solution goes here */2425 cout << pointsDistance << endl;262728 }return 0;

Declare variables: x1, y1, x2, y2, xDist, yDist, pointsDistance as doublesInitialize xDist, yDist,…

Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to pointsDistance. The calculation is: Distance = √(x2 − x1)² + (y2-yl)² Ex: For points (1.0, 2.0) and (1.0, 5.0), pointsDistance is 3.0. 493714.3402758.qx3zqy7 1 #include 2 #include < 3 using namespace std; 4 5 int main() { 6 double x1: 7 double y1: 8 9 10 double xDist; double yDist: double pointsDistance: 11 12 13 14 15 16 17 18 19 20 double x2: double y2: xDist = 0.0; yDist = 0.0; pointsDistance = 0.0; cin >> x1; cin >> y1: cin >> x2;

Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to pointsDistance. The calculation is: Distance = √(x2 − x1)² + (y2-yl)² Ex: For points (1.0, 2.0) and (1.0, 5.0), pointsDistance is 3.0. 493714.3402758.qx3zqy7 1 #include 2 #include < 3 using namespace std; 4 5 int main() { 6 double x1: 7 double y1: 8 9 10 double xDist; double yDist: double pointsDistance: 11 12 13 14 15 16 17 18 19 20 double x2: double y2: xDist = 0.0; yDist = 0.0; pointsDistance = 0.0; cin >> x1; cin >> y1: cin >> x2;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to pointsDistance. The calculation is:
Distance = √(x2 − x1)² + (y2 − y1)²
Ex: For points (1.0, 2.0) and (1.0, 5.0), pointsDistance is 3.0.
493714.3402758.qp3zqy7
1 #include <iostream>
2 #include <cmath>
3 using namespace std;
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
int main() {
double x1:
double y1:
double x2:
double y2:
double xDist;
double yDist;
double pointsDistance:
xDist = 0.0;
yDist = 0.0;
pointsDistance = 0.0;
cin >> x1;
cin >> y1;
cin >> x2;
in
17-

&N&CNNNNE
21
22
cin >> y2:
/* Your solution goes here */
24
25 cout << pointsDistance << endl;
26
27
28 }
return 0;

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Find out if either: 21000 + 277 21000 + 291 21000 + 297 is prime . They do not have any prime factors less than 109. You can use Modular Exponentiation, but you may not use commands of the form“IsPrime[n]” or “NextPrime[n].”