Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface density of atoms for (a)a (100) plane and (b) a (110) plane. (Ans. (a) 8.86 x 104 cm-2, (b) 6.27 x 101" cm-2]
Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface density of atoms for (a)a (100) plane and (b) a (110) plane. (Ans. (a) 8.86 x 104 cm-2, (b) 6.27 x 101" cm-2]
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![HW(2 questions)
Determine the distance between nearest (110) planes in a simple cubic lattice with a
lattice constant of an = 4.83 Å. (y 7s
The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface
density of atoms for (a)a (100) plane and (b) a (110) plane.
(Ans. (a) 8.86 x 10+ cm-, (b) 6.27 x 10" cm-2]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F462ae9e2-fe65-450a-9b7b-46f783092aa5%2Fc0321bff-ced4-41ee-9591-50ff6d0aa790%2Fqr330di_processed.jpeg&w=3840&q=75)
Transcribed Image Text:HW(2 questions)
Determine the distance between nearest (110) planes in a simple cubic lattice with a
lattice constant of an = 4.83 Å. (y 7s
The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface
density of atoms for (a)a (100) plane and (b) a (110) plane.
(Ans. (a) 8.86 x 10+ cm-, (b) 6.27 x 10" cm-2]
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