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Determine the design shear strength of the given shape, using Fy=50 ksi. Blank 1 W14x53 A = 15.60 in ^2 d = 13.900 in. tw 3= 0.370 in. bf = 8.060 in. tf = 0.660 lin. 10-7/8 in. k = 1.2500 in k1 = 1.0000 lin gage 5-1/2 in. rt 2.150 in d/Af = 2.62 bx 541 00 in 4 Sx = 77 80 in 43 5.890 in ly = 57 70 in 4 Sy = 14 30 in A3 1.920 ry = Zx = Zy = J = Cw = in 87 10 in 43 22.00 in ^3 1.94 in.^4 2540 in ^6 a 3= 58 22 in. Wno =| 26 70 in ^2 Sw = 35.50 in 4 Qf = 16.80 in 43 Qw = 42.60 in.43

Determine the design shear strength of the given shape, using Fy=50 ksi. Blank 1 W14x53 A = 15.60 in ^2 d = 13.900 in. tw 3= 0.370 in. bf = 8.060 in. tf = 0.660 lin. 10-7/8 in. k = 1.2500 in k1 = 1.0000 lin gage 5-1/2 in. rt 2.150 in d/Af = 2.62 bx 541 00 in 4 Sx = 77 80 in 43 5.890 in ly = 57 70 in 4 Sy = 14 30 in A3 1.920 ry = Zx = Zy = J = Cw = in 87 10 in 43 22.00 in ^3 1.94 in.^4 2540 in ^6 a 3= 58 22 in. Wno =| 26 70 in ^2 Sw = 35.50 in 4 Qf = 16.80 in 43 Qw = 42.60 in.43

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Determine the design shear strength of the given shape, using Fy-50 ksi. Blank 1 W14x53 A = 15.60 in ^2 ... 13.900 in. tw = 0.370 in. bf = 8.060 in. tf = 0.660 in. 10-7/8 in. 1.2500 in. k1 = 1.0000 in. gage = 5-1/2 in. rt = 2.150 in d/Af = 2.62 541 00 in.^4 Sx = 77 80 in 43 5.890 57 70 14 30 in. = XI in 4 Sy | in 3 ry = 1.920 in. Zx = 87.10 in 43 Zy = 22.00 in ^3 J = 1.94 in ^4 Cw 2540 in.^6 a 58 22 in. Wno = 26 70 in.^2 Sw = Qf = 35.50 in ^4 16.80 in.3 Qw: 42.60 in.^3 |||| 11 I|||
Transcribed Image Text:Determine the design shear strength of the given shape, using Fy-50 ksi. Blank 1 W14x53 A = 15.60 in ^2 ... 13.900 in. tw = 0.370 in. bf = 8.060 in. tf = 0.660 in. 10-7/8 in. 1.2500 in. k1 = 1.0000 in. gage = 5-1/2 in. rt = 2.150 in d/Af = 2.62 541 00 in.^4 Sx = 77 80 in 43 5.890 57 70 14 30 in. = XI in 4 Sy | in 3 ry = 1.920 in. Zx = 87.10 in 43 Zy = 22.00 in ^3 J = 1.94 in ^4 Cw 2540 in.^6 a 58 22 in. Wno = 26 70 in.^2 Sw = Qf = 35.50 in ^4 16.80 in.3 Qw: 42.60 in.^3 |||| 11 I|||
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