Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject toa. Continuous lateral support. Blank 1b. An unbraced length of 10 ft with Cb = 1.0. Blank 2C. An unbraced length of 20 ft with Cb = 1.0. Blank 3W10x26...A =7,61in.^2d =10.300in.tw =0.260in.bf =5.770lin.tf =T=k =0.440in.8-1/4in.0.7400in.k1 =0.6875in.in.gage =2-3/4in.rt =1.540in.d/Af =4.07Ix =144.00in.^4Sx =27.90in.^3rX =4.350in.ly =Sy =ry =Zx =Zy =J =Cw =14.10in.^44.89in.^31.360in.31.30in.437.50in.430.40in.^4345in.^6a =47.14in.Wno =14.30in.^2Sw =Qf =9.05in.^45.99in.^3Qw =15.50in.^3

Given data Use W 10 x 26 of A242 Fy =50ksi Find- design flexural strength

Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to a. Continuous lateral support. Blank 1 b. An unbraced length of 10 ft with Cb = 1.0. Blank 2 C. An unbraced length of 20 ft with Cb = 1.0. Blank 3

Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to a. Continuous lateral support. Blank 1 b. An unbraced length of 10 ft with Cb = 1.0. Blank 2 C. An unbraced length of 20 ft with Cb = 1.0. Blank 3

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Bars

In civil engineering, bars refer to steel reinforcement bars or rebars. These are structural members primarily used for reinforcement purposes in masonry works. A bar is characterized by its cross-sectional area, which is negligible compared to its length. Bars are usually manufactured by steel which is uniform throughout the length, or by meshing multiple steel wires. Other materials of the bar include carbon steel, glass fiber, carbon fiber, and basalt fiber. The reinforcing bars are coated with epoxy resins and other materials to enhance some of their properties including corrosion resistance.

Question

Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to
a. Continuous lateral support. Blank 1
b. An unbraced length of 10 ft with Cb = 1.0. Blank 2
C. An unbraced length of 20 ft with Cb = 1.0. Blank 3
W10x26
...
A =
7,61
in.^2
d =
10.300
in.
tw =
0.260
in.
bf =
5.770
lin.
tf =
T=
k =
0.440
in.
8-1/4
in.
0.7400
in.
k1 =
0.6875
in.
in.
gage =
2-3/4
in.
rt =
1.540
in.
d/Af =
4.07
Ix =
144.00
in.^4
Sx =
27.90
in.^3
rX =
4.350
in.
ly =
Sy =
ry =
Zx =
Zy =
J =
Cw =
14.10
in.^4
4.89
in.^3
1.360
in.
31.30
in.43
7.50
in.43
0.40
in.^4
345
in.^6
a =
47.14
in.
Wno =
14.30
in.^2
Sw =
Qf =
9.05
in.^4
5.99
in.^3
Qw =
15.50
in.^3

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