Hhhhjjjkkkkkkkk Problem 2: Learning Outcome #3A river has an average width of 4 meters into the paper and flows steadily with an average velocity of Bm/s at Point A. The depth at A Is 1.2m. Determine the depth h after the flow falls 2 meters. Water canbe considered as inviscid and incompressible. The density of water is taken as p=1000kg/m² andg=9.81m/s². Gravity acts vertically downward.Hint: (i) the free surface, where A, are located, is a streamline and it is exposed to air, with a constantair pressure. (II) Bernoulli eqn. and conservation of mass in control volume form will be helpful.12mB2 m

Name: Hhhhjjjkkkkkkkk Problem 2: Learning Outcome #3A river has an average w
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Description: Hhhhjjjkkkkkkkk Problem 2: Learning Outcome #3A river has an average width of 4 meters into the paper and flows steadily with an average velocity of Bm/s at Point A. The depth at A Is 1.2m. Determine the depth h after the flow falls 2 meters. Water c

To determine the depth 'h' at Bgiven average velocity depth of A, and the depth from the point of A…

Answered: Determine the depth ha sible The

Elements Of Electromagnetics

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ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Hhhhjjjkkkkkkkk

Problem 2
: Learning Outcome #3
A river has an average width of 4 meters into the paper and flows steadily with an average velocity of B
m/s at Point A. The depth at A Is 1.2m. Determine the depth h after the flow falls 2 meters. Water can
be considered as inviscid and incompressible. The density of water is taken as p=1000kg/m² and
g=9.81m/s². Gravity acts vertically downward.
Hint: (i) the free surface, where A, are located, is a streamline and it is exposed to air, with a constant
air pressure. (II) Bernoulli eqn. and conservation of mass in control volume form will be helpful.
12m
B
2 m

Expert Solution

Step 1: Introduction

To determine the depth 'h' at B

given

average velocity $v subscript 2 equals 8 space m divided by s$
depth of A, $h subscript 1 equals 1.2 space m$ and the depth from the point of A is $h subscript 2 space equals 2 space m$
acceleration due to gravity, $g equals 9.8 space m divided by s squared$
density of water, $rho space equals 1000 space k g divided by m cubed$
average width = 4 m

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