Determine the current flowing through R₂, given: R₁ = 40, R₂ = 190, and ₁ = 8 A (Round the FINAL answer to one decimal place.) Ī E₁ R₁ www

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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**Title: Calculating Current in Parallel Circuits**

---

**Objective:**

Determine the current flowing through \( R_2 \) from the given circuit parameters:

- \( R_1 = 4 \, \Omega \)
- \( R_2 = 19 \, \Omega \)
- \( I_1 = 8 \, \text{A} \)

*Note: Round the final answer to one decimal place.*

---

**Circuit Diagram Explanation:**

The circuit diagram shows a parallel circuit with:

- A power source labeled \( E_T \)
- Two resistors labeled \( R_1 \) and \( R_2 \)
- An ammeter in series with \( R_1 \), measuring the current \( I_1 = 8 \, \text{A} \)

**Analysis:**

1. **Understanding Parallel Circuits:**
   - In parallel circuits, the voltage across each resistor is the same.
   - The total current is the sum of the currents through each branch.

2. **Applying Ohm’s Law:**
   - Voltage across \( R_1 \): \( V = I_1 \times R_1 \)

3. **Calculating Voltage across \( R_1 \):**
   \[
   V = 8 \, \text{A} \times 4 \, \Omega = 32 \, \text{V}
   \]

4. **Using the Voltage to Find Current through \( R_2 \):**
   - Since voltage is the same across \( R_2 \):
   \[
   I_2 = \frac{V}{R_2} = \frac{32 \, \text{V}}{19 \, \Omega}
   \]
   - Calculate \( I_2 \) and round to one decimal place.

*Final step involves actual calculation with a calculator.*

**Conclusion:**

This exercise demonstrates calculating current in a parallel circuit using Ohm’s Law and confirms the principle that voltage remains constant across parallel branches.
Transcribed Image Text:**Title: Calculating Current in Parallel Circuits** --- **Objective:** Determine the current flowing through \( R_2 \) from the given circuit parameters: - \( R_1 = 4 \, \Omega \) - \( R_2 = 19 \, \Omega \) - \( I_1 = 8 \, \text{A} \) *Note: Round the final answer to one decimal place.* --- **Circuit Diagram Explanation:** The circuit diagram shows a parallel circuit with: - A power source labeled \( E_T \) - Two resistors labeled \( R_1 \) and \( R_2 \) - An ammeter in series with \( R_1 \), measuring the current \( I_1 = 8 \, \text{A} \) **Analysis:** 1. **Understanding Parallel Circuits:** - In parallel circuits, the voltage across each resistor is the same. - The total current is the sum of the currents through each branch. 2. **Applying Ohm’s Law:** - Voltage across \( R_1 \): \( V = I_1 \times R_1 \) 3. **Calculating Voltage across \( R_1 \):** \[ V = 8 \, \text{A} \times 4 \, \Omega = 32 \, \text{V} \] 4. **Using the Voltage to Find Current through \( R_2 \):** - Since voltage is the same across \( R_2 \): \[ I_2 = \frac{V}{R_2} = \frac{32 \, \text{V}}{19 \, \Omega} \] - Calculate \( I_2 \) and round to one decimal place. *Final step involves actual calculation with a calculator.* **Conclusion:** This exercise demonstrates calculating current in a parallel circuit using Ohm’s Law and confirms the principle that voltage remains constant across parallel branches.
Expert Solution
Step 1: Given data

given here a circuit and asked to find the current through the R2.

Here we are assuming that A is the Ammeter for measuring the current.


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