Determine the current across R1 if Vi=5V. + V₁ 700uA 7.9mA 8.6mA D 0 ☆ 1k www R₁ R₂ 0.5 k + V₂

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Q: SA Solve for and is at +=0², 0+, and 00. V/₂ F www 6√№ +=0 050 www 3 AL + Vx www 201 5 ww 30v

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Q: 1000 VAR 18. For the power triangle, the apparent power is, 2000 VA O 500 VAR O 1000 VAR 866 VAR

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Q: Determine lo if Vi=5V. + V₁ 8.6mA O 0 O 7.9mA 700uA D + 1 k R₁ R₂ 0.5 k w + V₂

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.