A Y-Y three-phase circuit is shown below. Solve for the following: Line current of phase b = Blank 14Blank 2° A (2 decimals) Average power delivered to the load = Blank 3 W %3D (2 decimals) *use the last blank for the unit locos (4t-96') E $ IH in b cos(4t+ ) 2H, 42 lo cos (Ht+309); Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

A Y-Y three-phase circuit is shown below. Solve for the following: Line current of phase b = Blank 14Blank 2° A (2 decimals) Average power delivered to the load = Blank 3 W %3D (2 decimals) *use the last blank for the unit locos (4t-96') E $ IH in b cos(4t+ ) 2H, 42 lo cos (Ht+309); Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

A 1,500 kVA, 3-phase alternator is connected to an infinite busbar at constant voltage of 11,000 volts. The resistance and reactance per phase are 0.10 ohm and 2.4 ohms respectively. Solve for the maximum external load that the machine can supply when the machine is excited to give an emf of 12,500 volts. Draw the single line diagram.
QV A: For the power system shown, calculate fault current and when a 3-phase fault occurs at point F. The data are given below. Equipment XI X2 Rating 20% 20% 6% 2.50 50 MVA-II KV TI 10% 10% 10% 1/132 KV30 MVA LINE 1000 1000 3000 72 10% 10% 10% 132/11 KV30 MVA MI 25% 25% 6% 40 MVA,1IKV M2 25% 25% 40 MVA,1IKV Line MI G TI T2 MI Fault
7. System Model and Per Unit T1 Line T2 BE 31.25miles 3 Impedance Load R1+jXL-0.1+j0.5 p.u. 30 MVA 30 MVA 13 kV X-0.1 p.u. 14 kV 13/220 kV X-0.2 p.u. 35 MVA * Transformer T2 is composed of "three single-phase" transformers, each rated 40/3 MVA, 132.8:14 kV with a leakage reactance of 0.1 per unit. (a) Fill in the appropriate base values. Gen. G Trans. Ti Line Trans. T: Load New MVA Base New KV Base (b) Calculate the impedance values. Gen G Trans. T1 Line Trans. T2 Load p.u. Impedance
T 2 (3 T₂ (4) Machine 1 FLY Machine 2 Krossy 147 YA For the three-phase power system with single-line diagram, equipment ratings and per-unit reactances are given as follows: Machines 1 and 2: 120 MVA, 10.5 kV, X = X2 = 0.2, X₁ = 0.03, X = 0.03; Transformers 1 and 2: 120 MVA, 11D/115Y kV, X₁= X2 = X0 = 0.05. Select a base of 120 MVA, 115 kV for the transmission line. On that base, the series reactances of the line are X1 X2 = 0.3 and Xo = 2X1 per unit. With a nominal system voltage of 115 kV at bus 3, machine 2 is operating as a motor drawing 40 MVA at 0.8 power factor lagging. Compute the fault current for single-line-to-ground fault at bus 3
please can the answer come fast
The rating of generator is expressed in terms of kVA Select one: True False
2. The one-line diagram of a power system is shown in the figure. The three-phase power and line-line ratings are given below: Generator 1:50 MVA, 22 kV, X = 24% Generator 2:50 MVA, 22 kV, X = 24% Synchronous Motor: 15 MVA, 4.4 kV, X = 22.5% Transformer 1:40 MVA, 110Y/22A kV, X = 6.4% Transformer 2:40 MVA, 110Y/22A kV, X=6.4% 3-ph load: Delta connected, 18+ j24 0 per phase ww ww. The three-phase ratings of the three-winding transformer T3 are: Primary: Secondary: Tertiary: Y-connected Y-connected Y-connected 80 MVA, 110 kV 60 MVA, 22 kV 20 MVA, 4.4 kV Neglecting resistance, the leakage impedances are: Zps = 9.6% on 80 MVA, 110 kV Zpi = 7.2% on 80 MVA, 110 kV Z = 10% on 60 MVA, 22 kV Choose as base 100 MVA, 20 kV in the generator 1 circuit. Draw the complete per- unit impedance/reactance diagram. Line 1 Line 2 G2 i 42.35 a j 42.35 a T2 3-ph load
What size 60 degree Celsius conductors are required for a 9000 watt single-phase 120/240 volt generator? A. 12 AWGB. 10 AWGC. 8 AWGD. 6 AWG
Two single phase transformers A and B with equal turns ratio have reactance of j3.2 and j19.2 referred to secondary. When operated in parallel, the load sharing of 100 kW at 0.8 pf lag between A and B transformers would respectively be a) 75 kw and 25kw b) 60 kw and 40 kw c) 20 kw and 80 kw d) 25 kw and 75 kw
PLEASE SOLVE THIS WITH COMPLETE & HANDWRITTEN SOLUTION, THANK YOU SO MUCH!
5.5 kW, 1450 rpm. L-type equivalent circuit and parameters for a continuous sinusoidal phase of a star connected 3-phase ASM with line voltage 220 V and frequency 50 Hz are given as follows, ignoring core (iron) losses: R1=0.21 Ohm, R2=-0.18 Ohm, X1=X2-0.66 Ohm and Xm = 9.9 Ohm How many times the inrush current will be the rated current when the ASM is started directly? Answer options group 8.0815 2.6455 4.3763 7.1534 1.2558 6.3414 5.2280 3.7473
Calculate new per unit reactance of T2. Generator G: 15 MVA, 13.8 kV, X = 0.15 p.u. %3D Motor M1: 5 MVA, 13.8 kV, X = 0.15 p.u. %3D Motor M2: 5 MVA, 14.4 kV, X = 0.15 p.u. T: 25 MVA, 13.2 - 161 kV, X %3D 0.1 р.u. T;: 15 MVA, 13.8 –. 161 kV, X = 0.1 p.u. Line: j100 N (actual) Select a base of 100 MVA and 161 kV in the transmission line. M) T G Line (M2) 0.67 pu O 6.67 pu О 0.33 pu 0.015 pu cede