Determine the critical value if given: n1 = 25; n2 = 22:; HA : µ < 5 and the level of significance is 10%
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Determine the critical value if given: n1 = 25; n2 = 22:; HA : µ < 5 and the level of significance is 10%
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- Radon is a gas emitted from the ground that can collect in houses in buildings. At certain levels it can cause lung cancer. Radon concentrations are measured in picocuries per liter (pCi/L). A radon level of 4 pCi/L is considered “acceptable” Radon levels in a house vary from week to week. In one house, a sample of 6 weeks had the following readings for radon level (in pCi/L): 1.9 2.8 3.9 3.9 4.2 5.7 Find the variance and standard deviation (definitional formula). Show your work using a table.Suppose you computed r = 0.563 using n = 31 data points. Using the critical values table below, determine if the value of r is significant or not. df 1 2 3 4 5 6 7 8 9 10 CV (+ and -) 0.997 0.950 0.878 0.811 0.754 0.707 0.666 0.632 0.602 0.576 Select the correct answer below: df 11 12 13 14 15 16 17 18 19 20 CV (+ and -) 0.555 0.532 0.514 0.497 0.482 0.468 0.456 0.444 0.433 0.423 df 21 22 23 24 25 26 27 28 29 30 CV (+ and -) 0.413 0.404 0.396 0.388 0.381 0.374 0.367 0.361 0.355 0.349 r is significant because it is between the positive and negative critical values. r is not significant because it is between the positive and negative critical values. r is significant because it is not between the positive and negative critical values. r is not significant because it is not between the positive and negative critical values. df 40 50 60 70 80 90 100 CV (+ and -) 0.304 0.273 0.250 0.232 0.217 0.205 0.195Let x represent the hemoglobin count (HC) in grams per 100 milliliters of whole blood. The distribution for HC is approximately normal with μ = 14 for healthy adult women. Suppose that a female patient has taken 12 laboratory blood samples in the last year. The HC data sent to her doctor is listed below. We would like to know if the data indicates this patient has significantly high HC compared to the population. 14,19,16,14,19,19,14,21,17,17,14,17 Give the p-value and interpret the results. a) p = 0.0012; Based on 5% significance level, I will reject the null hypothesis and conclude this patient has a high HC level. b) p = 0.0012; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. c) p = 0.0023; Based on 5% significance level, I will reject the null hypothesis and conclude this patient has a high HC level. d) p = .1053; Based on 5% significance level, I will fail to reject the null hypothesis and…
- A large automobile insurance company selected samples of single and married male policyholders and recorded the number who made an insurance claim over the preceding three-year period. Z-value p-value Single Policyholders n₁ = 440 Number making claims = 88 a. Use a = 0.05. Test to determine whether the claim rates differ between single and married male policyholders. (to 2 decimals) (to 4 decimals) X Married Policyholders n2 = 840 Number making claims 126 We can conclude ✔ that there is the difference between claim rates. b. Provide a 95% confidence interval (to 4 decimals) for the difference between the proportions for the two populations. Enter negative answer as negative number. X * )A repeated measures study with n=26 participants produces a mean difference of M D = 3 points, SS=500 for the difference scores, and t=2.50. Calculate Cohen's d and r square (r2) to measure the effect size for this study.Las Vegas has seen increased competition from Singapore and Macau for customers in the casino resort industry. One measurement of success is the average length of stay by visitors. The data in this file show the number of days a random sample of visitors stayed at each location. a. Using α = 0.05 to determine if there is a difference in the average length of stay by visitors for the three locations. Follow the steps as outlined in the exercises. b. If warranted, perform a multiple comparison test to determine which pairs are different using α = 0.05. c. Verify your results using Excel.
- Interpret a P-value: The manufacturer of a medication designed to lower blood pressure claims that the mean systolic blood pressure for people taking their medication is less than 135. To test this claim, blood pressure is measured for a sample of 500 people who are taking the medication. The P-value for testing Ho: μ = 135 versus H₁: µ< 135 is P = 0.001. a. The manufacturer concludes that because the P-value is very small, we can be fairly certain that the mean pressure is less than 135, but we cannot conclude that it is a lot smaller. Is this conclusion justified?State the t critical value that would be used for a 99% interval based on a sample size of 37.Using a significance level of α = 0.05, state your conclusion in terms of H0.?
- A score that is 2 points higher than the sample mean has a z-score of z = 0.5 and a score of X = 44 has a z-score of -1.00What is the sample mean?Benign prostatic hyperplasia is a non-cancerous enlargement of the prostate gland that adversely affects the quality of life of millions of men. A study of a minimally invasive procedure for the treatment of this condition looked at pretreatment Quality of Life (QOL Base) and Quality of Life (QOL 3Mo) after 3 months on treatment. Quality of Life was rated using an ordinal scale of 0 to 6, where 0 is "Delighted" and 6 is "Terrible" Create a "Delta" column depicting the Difference between the Base and 3-month ratings Find the Mean of the Differences, Standard Deviation and Standard Error for the Delta values Is there a Significant Difference in Quality of Life 3 months after treatment? Find the tsat value and the corresponding p-value boundaries using Table CA large automobile insurance company selected samples of single and married male policyholders and recorded the number who made an insurance claim over the preceding three-year period. Single Policyholders Married Policyholders 721 = 575 n2 = 740 Number making claims = 115 Number making claims = 111 a. Use α = 0.05. Test to determine whether the claim rates differ between single and married male policyholders. z-value p-value We can conclude (to 2 decimals) X (to 4 decimals) that there is the difference between claim rates. b. Provide a 95% confidence interval (to 4 decimals) for the difference between the proportions for the two populations. Enter negative answer as negative number.
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