Determine the critical ? value for a 99% confidence level. b. Find the 99% confidence interval for ?.

Q: Suppose that you are interested in determining the average height of a person in a large city. You…

A: Solution: Given information: n= 400 Sample size  x=63 inches Sample mean s= 6 inches Sample standard…

Q: Give a 95% confidence interval for the true mean time the team spent preparing for the game.…

A:

Q: An article the Journal of the American Medical Association (1992) examined whether the true mean…

A: From the provided information, Sample size (n) = 25 Sample mean (x̅) = 98.25oF Sample standard…

Q: People were polled on how many books they read the previous year. Initial survey results indicate…

A: For (a) and (b), we need the formula for margin of error, MOE: MOE=zγ​(n​s​)where,zy=z-score for the…

Q: Recall the scenario: The mean age for all Foothill College students for the last few years is 33.2.…

A: Sample size and level of confidence affect the error bound.

Q: 2. Which is a better score: a score 82 on a test with a mean of 70 and a standard deviation of 8,…

A:

Q: The average test score in a particular class is m=30. If you scored a 40 and the class (sample)…

A: Introduction: Denote the score of a randomly selected student in a class as X. It is given that the…

Q: Suppose that the sample dataset of July 1 temperatures consisted of 64 observations and that these…

A: given data standard deviation s = 4 sample size n = 64

Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: Suppose a randomly selected sample of n = 54 men has a mean foot length of x = 25.5 cm, and the…

A: Given

Q: Q4. The standard deviation of the temperature in a large refridgeratored room should not exceed…

A:

Q: Suppose that the lengths of human pregnancies are normally distributed with a mean of 266 days and a…

A: a) Empirical rule: The probability of the observation lies within 1 standard deviation of the mean,…

Q: Suppose that the lengths of human pregnancies are normally distributed with a mean of 266 days and a…

A: given data normal distributionμ = 266σ = 17   empirical rule : approximately 68-95-99.7% data fall…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Givensample size(n)=64Mean(x)=69.0standard deviation(s)=5.0confidence level=95%

Q: What is the margin of error for a 99% CI for a mean, when the sample size is 12, the sample average…

A: Given: Sample size, n = 12 Sample mean, x = 52 Sample standard deviation, s = 13 It follows a…

Q: A sample of the reading scores of 30 fifth graders has mean of 62.the standard deviation of the…

A: Given,   Sample size = 30 Sample mean = 62 Population standard deviation = 15   The objective is to…

Q: The lengths of pregnancies in a small rural village are normally distributed with a mean of 263 days…

A:

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given95% confidence interval N=361 x = 59.1 seconds. z= 4.9 SecondsFind the margin of error?

Q: Suppose that a sample of 15 observations has resulted in a sample mean of 12.58 and a sample…

A: n1=15, mean X̄n1=12.58, sn1=0.512

Q: From a sample with n = 28, the mean number of televisions per household is 2 with a standard…

A: Suppose a random variable x defines the number of televisions per household.

Q: Use z scores to compare the given values. The tallest living man at one time had a height of 233 cm.…

A:

Q: Q4. The average ambunt of A researcher selects a randomsample of 10 cities of Pakistan and the…

A: Average amount of rainfall(μ0)=11.52 inches n=10 Average=7.42 Standard deviation =1.3 Therefore,…

Q: During rush hour, the traffic speed on a busy highway is found to have mean 42 mph and standard…

A:

Q: A camp director is interested in the mean number of letters each child sends during his or her camp…

A: Confidence interval for mean is given by, (X bar + - z* s/√n) Here x bar = 7.7, s= 2.7 and n= 20  Z…

Q: Q2. You collected 500 weeks of data (2500 days total). Based on that you find Tuesday's mean return…

A: There are total 500 weeks. Therefore, total 500 Tuesdays are calculated.The mean return of Tuesdays…

Q: Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24…

A: The given data is as follows:Sample mean difference, Sample size, Sample standard deviation…

Q: From a normally distributed population, we took a simple random sample of 700 students with a mean…

A:

Q: he personal trainer collected data from a randomly selected sample of days. From this he found that…

A: Glasses(x) Frequency (f) x f 1 2 2 2 4 8 3 5 15 4 9 36 5 x 5x 6 9 54 7 4 28 Total…

Q: Assume that females have pulse rates that are normally distributed with a mean of p=75.0 beats per…

A: 1) c) Since the original population has a normal distribution, the distribution of a sample means…

Q: From a sample with n = 32, the mean number of televisions per household is 4 with a standard…

A:

Q: . A sample of 84 WCC students found mean age 24.7 years old with standard deviation 7.9 years old.…

A:

Q: Assume the average amount of days a patient spends in hospital is believed to be 14 days and a…

A: Given Mean=Xbar=12.5 Standard deviation=sigma=4.8 n=sample size=33 mu=14 Alpha=0.05

Q: Suppose you want to do a confidence interval for the mean age of your clients when X has a normal…

A: Given that, Critical values: Using the z-table, the critical value at 95% confidence level is

Q: In a survey 26 people where asked how much they spent on their child's birthday gift.  The results…

A: We have given that  Sample size=n=26 Mean=Xbar=50.9 Standard deviation=S=9.4 90% confidence interval…

Q: A study of 77 golfers showed that their average score on a particular course was 93. The st.dev. of…

A: 1). Assume, μ  be the population mean golfers score. x be the random variable representing the…

Q: HUMBE! 8f televisions per household is 3 with a standard deviation of 1 television. Using…

A: The mean is 3 and the standard deviation is 1.

Q: Use the confidence interval to find the margin of error and the sample mean (0.586,0.730) The margin…

A: Given that,Confidence interval = (0.586, 0.730)

Q: In 1977, men who were under 50 years old had a mean weight of 175 pounds, with a standard deviation…

A: Given: mean(μ)=175standard deviation(σ)=18

Q: A randomly selected sample of n = 75 individuals over 65 years old takes a test of memorization…

A: Given,sample size(n)=75sample mean(x¯)=53standard deviation(s)=7.4

Q: Heights of men on a baseball team have a bell-shaped distribution with a mean of 177 cm and a…

A:

Q: For men heights are normally distributed with a mean of 69 inches and a standard deviation of 2.8…

A: The random variable X is heights of the men. It is normally distributed. X~N(μ=69,σ=2.8) The sample…

Q: A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 66…

A:

Q: From a sample with n = 16, the mean number of televisions per household is 4 with a standard…

A: Chebyshev's theorem and empirical rule are used to calculate the percentages of data lies within…

Q: Use z scores to compare the given values. The tallest living man at one time had a height of 221 cm.…

A: Given, Let X be the height of the person Height of the tallest man living, X1=221 cm Height of the…

Q: Suppose you take a random sample of n = 80 Douglas College students and ask each student their age.…

A: Solution: Let X be the age of Douglas college students. From the given information, x-bar=22.0375…