Determine the convergence or divergence of the series. 2 n(n+3) Step 1 Decompose to partial fractions. Step 2 n=1 n=1 Write the sum Sp. Step 4 n(n+3) Therefore, Sn = [(-¹)+(-) + (− ² ) + ( ² - Sn= Σ( n=1 1 = ²/3 [ ( ² + + + + + + / -¯- 0 + ¹ ) + (n ² ₂ - 0 ²+ ₁) + (n ² ₁ - ² + ₂) + (1 - 1 Evaluate the sum. n=1 2 (n)(n+3) Step 3 Observe that appears as both positive and negative in the series. Thus, it will get cancelled. Similarly, will also get cancelled. The terms like 1, 2, and that do not have their additive inverses will not get cancelled. 7. 3 = lim Sn n-* lim n10 n+3 n+3 n+3 X n+3 ²3 ( + + + + + + + ² - ² + ₁ - X n+2 7 + ... n+3 n+3)]. -n+3)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 67E
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Determine the convergence or divergence of the series.
Step 1
Step 2
Decompose to partial fractions.
Step 3
∞
n = 1
n = 1
Step 4
Write the sum Sn.
Therefore,
2
n(n + 3)
Observe that
2
n(n + 3)
Sn = ²3² [( ²¹ ) + (-1/2-1/2) + (-1)+(²+3x
4
n = 1
1
1
1
1
+ (n ² ₂ - 0 ²¹² ₁) + (n ² ₁ - ² / ₂ ) + (-1/2 -
+ 1
²
1
- 2
n+ 2
Sn = ²3/[(1/2
+
Evaluate the sum.
Σ(-
n = 1
21/12/23
2
(n)(n+3)
+
appears as both positive and negative in the series. Thus, it will get cancelled. Similarly,... will also get cancelled. The terms like 1, and
2'
1
3
=
lim Sn
1
n + 1
n→∞
= lim
2/1
n→∞ 37
W|N
3
1
11
2
n+3
n+3
1
1
1
3 n+ 1
n+3
n+2
1
n+ 3
1
n+3)].
n+ 3
that do not have their additive inverses will not get cancelled.
Transcribed Image Text:Determine the convergence or divergence of the series. Step 1 Step 2 Decompose to partial fractions. Step 3 ∞ n = 1 n = 1 Step 4 Write the sum Sn. Therefore, 2 n(n + 3) Observe that 2 n(n + 3) Sn = ²3² [( ²¹ ) + (-1/2-1/2) + (-1)+(²+3x 4 n = 1 1 1 1 1 + (n ² ₂ - 0 ²¹² ₁) + (n ² ₁ - ² / ₂ ) + (-1/2 - + 1 ² 1 - 2 n+ 2 Sn = ²3/[(1/2 + Evaluate the sum. Σ(- n = 1 21/12/23 2 (n)(n+3) + appears as both positive and negative in the series. Thus, it will get cancelled. Similarly,... will also get cancelled. The terms like 1, and 2' 1 3 = lim Sn 1 n + 1 n→∞ = lim 2/1 n→∞ 37 W|N 3 1 11 2 n+3 n+3 1 1 1 3 n+ 1 n+3 n+2 1 n+ 3 1 n+3)]. n+ 3 that do not have their additive inverses will not get cancelled.
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