determine the computed value.
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Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…
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Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…
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Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…
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Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…
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Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…
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Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…
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Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…
A: Hi! Thank you for the question. As per the honor code, we are allowed to answer three sub-parts at a…
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Q: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest…
A: Given : x= 78.6 x̄ = 15.15 s = 21.46
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A: It is given that Mean = 1.8Standard deviation = 0.2
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A soda manufacturer is interested in determining whether its bottling machine tends to overfill. Each bottle is supposed to contain 12 ounces of fluid. A random sample of 25 bottles was taken and found that the
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- Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 72.6 Mbps. The complete list of 50 data speeds has a mean of x=18.29 Mbps and a standard deviation of s=19.75 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? Question content area bottom Part 1 a. The difference is 54.3154.31 Mbps. (Type an integer or a decimal. Do not round.) Part 2 b. The difference is enter your response here standard deviations. (Round to two decimal places as needed.)FInd the Dispersion (Range, Variance, Standard Deviation, Coefficient of Variation - whichever is appropriate to the variable).The length of time it takes for a worker to perform certain task (in minutes) was recorded for 10 workers. The resulting data values were the following: 5, 3, 11, 7, 6, 9, 4, 8, 7, 10 Find the mean, median, mode, range, variance and standard deviation. In the answers for the mean, variance, and standard deviation leave one digit after decimal point. a. Mean = d. Range = b. Median = e. Variance = c. Mode = f. Standard deviation =
- Use the Empirical Rule. The mean speed of a sample of vehicles along a stretch of highway is 68 miles per hour, with a standard deviation of 3 miles per hour. Estimate the percent of vehicles whose speeds are between 65 miles per hour and 71 miles per hour. (Assume the data set has a bell-shaped distribution.) Approximately nothing% of vehicles travel between 65 miles per hour and 71 miles per hour.Find the standard deviation.. Round to one more place than the data 7,19,20,8,17, 14, 8, 20, 12 O A. 5.1 O B. 1.7 O C. 5.4 O D. 5.7Researchers collected information on the body parts of a new species of frog. The thumb length for the female frog has a mean of 8.28 mm and a standard deviation of 0.78 mm. Let x denote thumb length for a female specimen. a. Find the standardized version of x. b. Determine and interpret the z-scores for thumb lengths of 10.3 mm and 7.1 mm. Round your answers to two decimal places. a. Find the standardized version of x. z=enter your response here
- Use the following information for the question. The average travel time to work for a person living and working in Kokomo, Indiana is 17 minutes. Suppose the standard deviation of travel time to work is 4.5 minutes and the distribution of travel time is approximately normally distributed.Which of these statements is asking for a measurement (i. e. is an inverse normal question)? A.What percentage of people living and working in Kokomo have a travel time to work that is between thirteen and fifteen minutes? B.If 15% of people living and working in Kokomo have travel time to work that is below a certain number of minutes, how many minutes would that be?A data set lists weights (Ib) of plastic discarded by households. The highest weight is 5.72 Ib, the mean of all of the weights is x= 2.345 lb, and the standard deviation of the weights is s =2.123 lb. a. What is the difference between the weight of 5.72 lb and the mean of the weights? b. How many standard deviations is that (the difference found in part (a))? c. Convert the weight of 5.72 Ib to a z score d. If we consider weights that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the weight of 5.72 Ib significant? a. The difference is lb. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal places as needed.) c. The z score is z= (Round to two decimal places as needed.) d. The highest weight isHuman body temperatures for healthy individuals have approximately a normal distribution with mean 98.25 °F and standard deviation .75 °F. (The past accepted value of 98.6 Fahrenheit was obtained by converting the Celsius value of 370, which is correct to the nearest integer.) a. Find the 90th percentile of the distribution. b. Find the 5th percentile of the distribution. c. What temperature separates the coolest 25% from the others?
- A musicologist is attempting to determine the mean length of modern pop songs. She conducts a sample of 40 songs, and finds a sample mean of 214 seconds., with a standard deviation of 10 secods. Assume that the distribution of lengths of pop songs is nearly normal.Define your variable: Let p be the proportion of pop song that are seconds long. Let μμ be the mean length of the sampled pop songs, in seconds. Let μμ be the mean length of pop songs, in seconds.. Let p be the proprotion of songs in the sample. Create and interpret a 95% Confidence Interval. Round your answers to one decimal place. and seconds.What is the margin of error? Round your answer to one decimal place. seconds.According to Google, the mean length of pop songs is 210210. What do you think of this claim? The claim is inside the interval. It is reasonable. The claim is above the sample mean, so there is no way it can be true. The claim is inside the interval. It must be true. That claim is not in our…Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 73.7 Mbps. The complete list of 50 data speeds has a mean of x = 16.05 Mbps and a standard deviation of s = 17.75 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? ..... a. The difference is Mbps. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal places as needed.) c. The z score is z = (Round to two decimal places as needed.) d. The carrier's highest data speed is Next MacBook F12 DD F11 DII F10 F9 F8 888 00 F7 F6 F5 F4 F3 F2 F1 & ! @ # $ 7 8 4 5 6…
