DETERMINE THE BEARING, LATITUDE AND DEPARTURE OF EACH COURSE, ADJUSTED LATITUDES AND DEPARTURES OF EACH COURSE BY APPLYING THE COMPASS RULE, AREA OF THE TRACT OF LAND DEFINED BY THE TRAVERSE (EMPLOYING DOUBLE MERIDIAN DISTANCES, AREA OF THE SAME TRACT (EMPLOYING DOUBLE PARALLEL DISTANCES), LINEAR ERROR OF CLOSURE AND BEARING OF THE SIDE OF ERROR, AND RELATIVE ERROR OF CLOSURE.

DETERMINE THE BEARING, LATITUDE AND DEPARTURE OF EACH COURSE, ADJUSTED LATITUDES AND DEPARTURES OF EACH COURSE BY APPLYING THE COMPASS RULE, AREA OF THE TRACT OF LAND DEFINED BY THE TRAVERSE (EMPLOYING DOUBLE MERIDIAN DISTANCES, AREA OF THE SAME TRACT (EMPLOYING DOUBLE PARALLEL DISTANCES), LINEAR ERROR OF CLOSURE AND BEARING OF THE SIDE OF ERROR, AND RELATIVE ERROR OF CLOSURE.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q.4. Compute by DMDs the area in hectares within a closed-polygon traverse ABCDEFA by placing the X and Y axes through the most southerly and most westerly stations, respectively. Departures and latitudes (in meters) follow. AB: E dep. 30, N lat. = 40; BC: E dep. = 70, N lat. = 10; CD = E dep. = 30, S lat = 50; DE: W dep = 60, S lat. = 40; EF: W dep = 90, S lat = 30; FA: E dep. = 20, N lat = 70.
An irregular lot was surveyed to obtain its area. Compute for the lot’s area using DPD method. (Balance the traverse using the Compass Rule). The obtained data are as follows:
A triangular lot has interior angles ABC, with value 44.06°, 54.49°, and 82.01° respectively. What is the angular error of closure? O 33'36" O 0.58 O 33°36' 0'50"
11. ADJUSTMENT OF LENGTHS AND BEARINGS. Given in the accom- panying tabulation tures for a property survey. and adjusted bearing of each course. Tabulate all given and computed values accordingly. are the adjusted latitudes and depar- Determine the adjusted length ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N +E - W 117.09 176.83 1-2 1 03.82 2-3 3.67 3-4 166.64 20.34 4-5 27.65 224.05 5-1 86.80 90.21 Sums +194.29 -194.29 +314.26 -314.26 (ENL) ESL) (ΣΕD ) (EWD)
A surveyor forgot to note the distance and bearing of a line while performing a close traverse. Assuming that there was no error while performing the survey, what would be the value of the distance and bearing of course 9-1. Plot the traverse using an appropriate scale. LINE DISTANCE (feet) BEARING 1-2 953.9793 N 36.58° E N 77.58° E S 38.470 E S 38.29° W N 19.530 W S 70.47° W S 12.29° W N 62.64° W 2-3 520.3718 3-4 1121.4479 4-5 986.9961 5-6 721.5146 6-7 334.3818 7-8 502.2802 8-9 543.1215 9-1
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How to determine the distance of the other end of the dividing line D along the side AB measured from A?
13. A surveyor needs to determine the coordinate of an inaccessible location, point C. Setting up on point A, they sight point B (due east of point A) and set 0 on their total station. The measured distance between A and B is 400 m. The surveyor points the total station at point C (north of point B and east of point A) and reads an angle to the right of 340°20'15". Given that the UTM coordinate of point A is 680100.455 mE, 4912081.750 mN (UTM 17T, NAD83) what are the coordinates of points B and C?
Compute by DMDs the area in hectares within a closed-polygon traverse ABCDEFA by placing the X and Y axes through the most southerly and most westerly stations, respectively. Departures and latitudes (in meters) follow.AB: E dep. = 30, N lat. = 40; BC: E dep. = 70, N lat. = 10; CD: E dep. = 30, S lat. = 50; DE: W dep. = 60, S lat. = 40; EF: W dep. = 90, S lat. = 30; FA: E dep. = 20, N lat. = 70
Latitude & Departure Problem B For the traverse sketch shown below, complete the latitude and departure calculations, determine the error of closure and relative accuracy. Start at Point A and work counter – clockwise around the loop Course Bearing Distance Cos Sin Latitude Departure Then adjust the traverse using compass rule
10. The algebraic sum of latitude and departure of a five-sided tract of land ABCDE are as follows: EL = - 1.45m, ED = + 1.25 m. Determine the error of closure.