Determine if the series converges or diverges. Use any method, and give a reason for your answer. n-5 Σ M8 n=5 n7" Does the series converge or diverge? Select the correct choice below and, if necessary, fill in the answer box within your choice. 00 Ο A. Because Σ · Σ n-5 n=5 n7" OC. Because ∞ n-5 Ο B. Because Σ -> [ n=5 n7" OD. Since lim OF. Since n=5 n7" ∞ E. Because Σ 8 n→∞ n7" 5 n-5 n-5 n-5 n7" n=5 n7" = = M88 M8 n-5 2 S n=5 n=5 M8 1 -|C Σ n=5 n 1 n and ∞ and converges, the series converges by the Direct Comparison Test. 1 n=57" Σ · and Σ n=5 n=5 ∞ |- 1 n n=5 1 n the given series diverges by the nth-Term Test for Divergence. diverges, the series diverges by the Direct Comparison Test. 1 converges, the series converges by the Direct Comparison Test. ∞ 1 1 · and Σ diverges, the series diverges by the Direct Comparison Test. 77 n=5 the given series diverges by the Integral Test.

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Chapter1: Functions And Models
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Determine if the series converges or diverges. Use any method, and give a reason for your answer.

\[
\sum_{n=5}^{\infty} \frac{n-5}{n7^n}
\]

---

Does the series converge or diverge? Select the correct choice below and, if necessary, fill in the answer box within your choice.

- ○ A. Because \(\sum_{n=5}^{\infty} \frac{n-5}{n7^n} \leq \sum_{n=5}^{\infty} \frac{1}{n} \) and \(\sum_{n=5}^{\infty} \frac{1}{n} \) converges, the series converges by the Direct Comparison Test.

- ○ B. Because \(\sum_{n=5}^{\infty} \frac{n-5}{n7^n} \geq \sum_{n=5}^{\infty} \frac{1}{n} \) and \(\sum_{n=5}^{\infty} \frac{1}{n} \) diverges, the series diverges by the Direct Comparison Test.

- ○ C. Because \(\sum_{n=5}^{\infty} \frac{n-5}{n7^n} \leq \sum_{n=5}^{\infty} \frac{1}{7^n} \) and \(\sum_{n=5}^{\infty} \frac{1}{7^n} \) converges, the series converges by the Direct Comparison Test.

- ○ D. Since \(\lim_{{n \to \infty}} \frac{n-5}{n7^n} = \, \text{[ ]} \), the given series diverges by the nth-Term Test for Divergence.

- ○ E. Because \(\sum_{n=5}^{\infty} \frac{n-5}{n7^n} \geq \sum_{n=5}^{\infty} \frac{1}{7^n} \) and \(\sum_{n=5}^{\infty} \frac{1}{7^n} \) diverges, the series diverges by the Direct Comparison Test.

- ○ F. Since \(\int_{5}^{\in
Transcribed Image Text:Determine if the series converges or diverges. Use any method, and give a reason for your answer. \[ \sum_{n=5}^{\infty} \frac{n-5}{n7^n} \] --- Does the series converge or diverge? Select the correct choice below and, if necessary, fill in the answer box within your choice. - ○ A. Because \(\sum_{n=5}^{\infty} \frac{n-5}{n7^n} \leq \sum_{n=5}^{\infty} \frac{1}{n} \) and \(\sum_{n=5}^{\infty} \frac{1}{n} \) converges, the series converges by the Direct Comparison Test. - ○ B. Because \(\sum_{n=5}^{\infty} \frac{n-5}{n7^n} \geq \sum_{n=5}^{\infty} \frac{1}{n} \) and \(\sum_{n=5}^{\infty} \frac{1}{n} \) diverges, the series diverges by the Direct Comparison Test. - ○ C. Because \(\sum_{n=5}^{\infty} \frac{n-5}{n7^n} \leq \sum_{n=5}^{\infty} \frac{1}{7^n} \) and \(\sum_{n=5}^{\infty} \frac{1}{7^n} \) converges, the series converges by the Direct Comparison Test. - ○ D. Since \(\lim_{{n \to \infty}} \frac{n-5}{n7^n} = \, \text{[ ]} \), the given series diverges by the nth-Term Test for Divergence. - ○ E. Because \(\sum_{n=5}^{\infty} \frac{n-5}{n7^n} \geq \sum_{n=5}^{\infty} \frac{1}{7^n} \) and \(\sum_{n=5}^{\infty} \frac{1}{7^n} \) diverges, the series diverges by the Direct Comparison Test. - ○ F. Since \(\int_{5}^{\in
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