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Given the power series 00 2 A x(n + 3) n = 0 1. Force the Exponent "n + 3" to be "R" like we did in the last lesson.

Given the power series 00 2 A x(n + 3) n = 0 1. Force the Exponent "n + 3" to be "R" like we did in the last lesson.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the power series 00 Σ E A x(n + 3) n = 0 1. Force the Exponent "n + 3" to be "R" like we did in the last lesson. 2. Now use what we have learned in this lesson to force the new series to start at "R = 5". 00 00 A EA x(n + 3) È (R - 3) A (R - 3) ** n = 0 R = 0 00 00 ®E A, xu + 3) = E (R - 3) A, x* Σ Α.xd+ B n = 0 R = 1 00 Ž A, xle + 3) = E A (« - 3) 00 (R - 3) n = 0 R = 0 Ο ΣΑ. A, xla + 3) A *(R - 3) ** n = 0 R = -3 00 00 Θ Σ (E 2 A x(m g(n + 3) = E A, x* n = 0 R = 0 00 Ž 4, xl* + *) = E A (R - 3) ** 00 F n = 0 R = 3
Transcribed Image Text:Given the power series 00 Σ E A x(n + 3) n = 0 1. Force the Exponent "n + 3" to be "R" like we did in the last lesson. 2. Now use what we have learned in this lesson to force the new series to start at "R = 5". 00 00 A EA x(n + 3) È (R - 3) A (R - 3) ** n = 0 R = 0 00 00 ®E A, xu + 3) = E (R - 3) A, x* Σ Α.xd+ B n = 0 R = 1 00 Ž A, xle + 3) = E A (« - 3) 00 (R - 3) n = 0 R = 0 Ο ΣΑ. A, xla + 3) A *(R - 3) ** n = 0 R = -3 00 00 Θ Σ (E 2 A x(m g(n + 3) = E A, x* n = 0 R = 0 00 Ž 4, xl* + *) = E A (R - 3) ** 00 F n = 0 R = 3
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