Determine (i) f ( x ) (iї) k

Q: Find the requested function and state the domain. 6 (g o f)(x) for f(x) = and g(x) = 2-x 6

A: Given : fx = 6x6gx = 2-x

Q: Find (f ∘ f )(-1).

A:

Q: i = √ √ 3x² (x³ + 1)²³ dx, w= x³+1 Rewrite the Function in terms of u

A: The objective of the question is evaluate the definite integral and rewriting the integral.

Q: Given f(x) = 23 10x, evaluate the following. (a) (f of-)(42) = (b) (f o f)(40) = %3D

A: First we will calculate the inverse of f. Then see that the composition of f and f inverse works…

Q: f(x) = Vx+9– 10.

A: We can solve the given problem using concept of function.

Q: Let f(x) = and g(x) = - Find and simplify: (f + g)(x) Select one: A. x²+3x-1 x(x-1) B. -x+3x+1…

A:

Q: Given f(r, y) 3z - 4ry 6y, find f-(1, y) = fu(z, y) =

A: Given f(x,y)=-3x3-4xy3-6y5

Q: Let g(x)=31-x. Compute: a) g(2.3) b) g(2) c) g(-1)

A: Given that

Q: if f(x) = 3 and g(x) = f(x) – 1 then (f .g)(-3) О а.-3 O b. 6 C. 9 Od. 27

A:

Q: 9. f(x) = Зх + 4 Then f(x + h) – f(x) A h (3x + 4)(Bx + C + Dh) Find A, B, C, and D. A = B = C = and…

A:

Q: R= {(x,y) | X is the sister of y}

A: This is question of algebra Here set is given We have to find components of it Further calculation…

Q: b) h(x) - 13 — 2х - х?). c) h(x) = V3 - x 5, d) h(x) = Vx³ + 4x2 + 1.

A:

Q: y = (c1 + c2x)ex + c3e2x

A:

Q: If f(x) = x2 + 3x - 1, find:

A: Given:fx=x2+3x-1fa+h-fah

Q: f4

A:

Q: e-X f(x, у) %3D x2 + y2

A:

Q: )

A:

Q: If f(x) = ax, show that f(A + B) = f(A) . f(B).

A: given: fx=ax we have to show that f(A + B) = f(A) . f(B)

Q:

A: Given,       x-x=

Q: f(x) = /x2 + 1 x²

A: Find the domain

Q: Let f(x) = 9x +3 f f '(x) =

A: Given a function. We need to find its inverse.

Q: Let f(x) = 1 and g(x) +4. Then (fo g)(æ) (go f)(x) =

A: (f o g)(x) = x/6 (g o f)(x) =(4x -10)/(x-4)

Q: Q) Let f(x) = . Find f %3D

A:

Q: Evaluate (f− g) , (1) and (3f + 2g) , (1), assuming that f , (1) = 3 and g , (1) = 5.

A:

Q: y=x2x(x>0,x≠1)

A: Dear student, Since what is to find is not mentioned in the question and you have posted the…