Determine how many atoms of each element are on each side of the equation. Also, determine if the equation is balanced. a. HCI + Ca === CaCl₂ + H₂ b. TiCla+ 2 H₂O === TiO2 + HCI C. Al(OH)3 + H3PO4 === AIPO4 + 3H₂O
Determine how many atoms of each element are on each side of the equation. Also, determine if the equation is balanced. a. HCI + Ca === CaCl₂ + H₂ b. TiCla+ 2 H₂O === TiO2 + HCI C. Al(OH)3 + H3PO4 === AIPO4 + 3H₂O
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Balancing Chemical Equations: Counting Atoms**
**Problem 3: Determine the number of atoms of each element on either side of the chemical equation. Additionally, verify if the equation is balanced.**
**Given Equations:**
a. \( \text{HCl} + \text{Ca} \rightarrow \text{CaCl}_2 + \text{H}_2 \)
b. \( \text{TiCl}_4 + 2 \text{H}_2\text{O} \rightarrow \text{TiO}_2 + \text{HCl} \)
c. \( \text{Al(OH)}_3 + \text{H}_3\text{PO}_4 \rightarrow \text{AlPO}_4 + 3 \text{H}_2\text{O} \)
**Detailed Explanation:**
For each equation, count the atoms of each element present on both the reactant side and the product side.
**a. HCl + Ca → CaCl₂ + H₂**
- Reactant side:
- H: 1 (from HCl)
- Cl: 1 (from HCl)
- Ca: 1 (from Ca)
- Product side:
- H: 2 (from H₂)
- Cl: 2 (from CaCl₂)
- Ca: 1 (from CaCl₂)
To balance the equation, ensure the number of atoms for each element are equal on both sides:
\[
2\text{HCl} + \text{Ca} \rightarrow \text{CaCl}_2 + \text{H}_2
\]
Now the counts are balanced:
- H: 2
- Cl: 2
- Ca: 1
**b. TiCl₄ + 2 H₂O → TiO₂ + HCl**
- Reactant side:
- Ti: 1 (from TiCl₄)
- Cl: 4 (from TiCl₄)
- H: 4 (from 2 H₂O)
- O: 2 (from 2 H₂O)
- Product side:
- Ti: 1 (from TiO₂)
- Cl: 1 (from HCl)
- H: 1 (from HCl)
- O: 2 (from TiO₂)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9a7b46e8-8a33-44cb-988f-05793dec8601%2Fd97105da-fdec-413c-9a58-7c2d8d8f72c9%2Fgbfwg0n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Balancing Chemical Equations: Counting Atoms**
**Problem 3: Determine the number of atoms of each element on either side of the chemical equation. Additionally, verify if the equation is balanced.**
**Given Equations:**
a. \( \text{HCl} + \text{Ca} \rightarrow \text{CaCl}_2 + \text{H}_2 \)
b. \( \text{TiCl}_4 + 2 \text{H}_2\text{O} \rightarrow \text{TiO}_2 + \text{HCl} \)
c. \( \text{Al(OH)}_3 + \text{H}_3\text{PO}_4 \rightarrow \text{AlPO}_4 + 3 \text{H}_2\text{O} \)
**Detailed Explanation:**
For each equation, count the atoms of each element present on both the reactant side and the product side.
**a. HCl + Ca → CaCl₂ + H₂**
- Reactant side:
- H: 1 (from HCl)
- Cl: 1 (from HCl)
- Ca: 1 (from Ca)
- Product side:
- H: 2 (from H₂)
- Cl: 2 (from CaCl₂)
- Ca: 1 (from CaCl₂)
To balance the equation, ensure the number of atoms for each element are equal on both sides:
\[
2\text{HCl} + \text{Ca} \rightarrow \text{CaCl}_2 + \text{H}_2
\]
Now the counts are balanced:
- H: 2
- Cl: 2
- Ca: 1
**b. TiCl₄ + 2 H₂O → TiO₂ + HCl**
- Reactant side:
- Ti: 1 (from TiCl₄)
- Cl: 4 (from TiCl₄)
- H: 4 (from 2 H₂O)
- O: 2 (from 2 H₂O)
- Product side:
- Ti: 1 (from TiO₂)
- Cl: 1 (from HCl)
- H: 1 (from HCl)
- O: 2 (from TiO₂)
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