Determine force in rod ab The diagram displays a structural framework with a triangular configuration. The task is to determine the force in the rod labeled as "AD". ### Components:- **Point A**: The base point of the structure on the left side.- **Point D**: The apex of the structure at the top.- **Points A and D are connected by a steel rod**: - Cross-sectional area (A) = 0.5 square inches - Modulus of Elasticity (E) = 29,000 ksi- **Horizontal Beam at A**: - Length = 10 feet- **Vertical Component, from C to D**: This is a steel column. - Length = 18 feet - Moment of Inertia (I) = 750 (inches)^4 - Area (A) = 6 square inches - Modulus of Elasticity (E) = 29,000 ksi- **Load**: A force of 32 kips (kilo-pounds) is applied at the pin joint located at point D.### Notes:- The task is to determine the force in the rod AD, considering the effects of the applied load and the structural properties of the components.- The pin at point D allows rotational freedom but restrains translational movement in the plane of the diagram.- Units must be consistent when performing calculations, ensuring that dimensions are considered, especially when transitioning between feet and inches.This setup can be analyzed using static equilibrium equations and deformation compatibility conditions to solve for the unknown force in the rod AD.

Data given: Asked: Force in rod ABThe angle between A, B and C can be obtained by, ∠ABC = tanθ = 1018 = 0.555∴ θ = tan-1 0.5555∴ θ =29.055°Let's consider joint B Consider ∑H = 0, ∴ FAB sin(29.055°) = 32 ∴ FAB = 32sin29.055° = 65.89 k Therefore, the value of force in rod AB = 65.89 k