Determine and from the given parameters of the population and sample size. µ= 74, o = 6, n= 36 ..... H =
Determine and from the given parameters of the population and sample size. µ= 74, o = 6, n= 36 ..... H =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![**Problem Statement:**
Determine \(\mu_{\bar{x}}\) and \(\sigma_{\bar{x}}\) from the given parameters of the population and sample size.
**Given:**
- \(\mu = 74\)
- \(\sigma = 6\)
- \(n = 36\)
**Solution:**
The image includes a section indicating where to calculate these:
1. **Calculate \(\mu_{\bar{x}}\):**
\(\mu_{\bar{x}}\) is the mean of the sample means, and it is equal to the population mean \(\mu\).
\[
\mu_{\bar{x}} = \mu = 74
\]
2. **Calculate \(\sigma_{\bar{x}}\):**
\(\sigma_{\bar{x}}\) is the standard deviation of the sample means (standard error of the mean) and is calculated as follows:
\[
\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} = \frac{6}{\sqrt{36}} = \frac{6}{6} = 1
\]
**Results:**
- \(\mu_{\bar{x}} = 74\)
- \(\sigma_{\bar{x}} = 1\)
The image includes a placeholder box to input \(\mu_{\bar{x}}\) beneath the problem statement. There are no graphs or diagrams present, just text and a space for calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe55ca600-6ecd-431e-a2f3-7959f6a21e5c%2F2758d5fc-df99-45d3-8ee4-b36085cc68f2%2Fystyteg_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Determine \(\mu_{\bar{x}}\) and \(\sigma_{\bar{x}}\) from the given parameters of the population and sample size.
**Given:**
- \(\mu = 74\)
- \(\sigma = 6\)
- \(n = 36\)
**Solution:**
The image includes a section indicating where to calculate these:
1. **Calculate \(\mu_{\bar{x}}\):**
\(\mu_{\bar{x}}\) is the mean of the sample means, and it is equal to the population mean \(\mu\).
\[
\mu_{\bar{x}} = \mu = 74
\]
2. **Calculate \(\sigma_{\bar{x}}\):**
\(\sigma_{\bar{x}}\) is the standard deviation of the sample means (standard error of the mean) and is calculated as follows:
\[
\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} = \frac{6}{\sqrt{36}} = \frac{6}{6} = 1
\]
**Results:**
- \(\mu_{\bar{x}} = 74\)
- \(\sigma_{\bar{x}} = 1\)
The image includes a placeholder box to input \(\mu_{\bar{x}}\) beneath the problem statement. There are no graphs or diagrams present, just text and a space for calculations.
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