Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![### Educational Content: Trigonometry and Right Triangles
#### Diagram Analysis
The image features a right triangle with the following dimensions:
- **Opposite side**: 16 units
- **Hypotenuse**: 27 units
The angle opposite the side measuring 16 units is denoted as \( x^\circ \).
#### Problem Statement
**BONUS Question:**
- You're tasked to round your answer to the nearest tenth.
- Sample answer provided: 4.2
#### Explanation
To find the angle \( x^\circ \), you can use trigonometric ratios. Specifically, the sine function is applicable here, as it relates the opposite side and the hypotenuse in a right triangle.
The formula is:
\[
\sin(x) = \frac{\text{opposite side}}{\text{hypotenuse}} = \frac{16}{27}
\]
To find \( x \), take the inverse sine (\(\sin^{-1}\)) of the result:
\[
x = \sin^{-1}\left(\frac{16}{27}\right)
\]
Once you calculate \( x \), round to the nearest tenth as instructed. The approximate sample answer is noted as 4.2 degrees.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F409cee4a-60f6-4aa4-afef-be7f51867a9b%2Fd19bd499-8a76-4653-b1a1-c361cb5ce8fb%2F5ao9c8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Educational Content: Trigonometry and Right Triangles
#### Diagram Analysis
The image features a right triangle with the following dimensions:
- **Opposite side**: 16 units
- **Hypotenuse**: 27 units
The angle opposite the side measuring 16 units is denoted as \( x^\circ \).
#### Problem Statement
**BONUS Question:**
- You're tasked to round your answer to the nearest tenth.
- Sample answer provided: 4.2
#### Explanation
To find the angle \( x^\circ \), you can use trigonometric ratios. Specifically, the sine function is applicable here, as it relates the opposite side and the hypotenuse in a right triangle.
The formula is:
\[
\sin(x) = \frac{\text{opposite side}}{\text{hypotenuse}} = \frac{16}{27}
\]
To find \( x \), take the inverse sine (\(\sin^{-1}\)) of the result:
\[
x = \sin^{-1}\left(\frac{16}{27}\right)
\]
Once you calculate \( x \), round to the nearest tenth as instructed. The approximate sample answer is noted as 4.2 degrees.
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