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Determine an appropriate number of classes and class width required to construct a grouped frequency distribution for data sets with the following values: a. n = 200 Minimum 33 Maximum = 345 Number of Classes: Class Width: Round to the nearest whole number b. n 92 Minimum Number of Classes: - - 0.22 Maximum 1.82

Determine an appropriate number of classes and class width required to construct a grouped frequency distribution for data sets with the following values: a. n = 200 Minimum 33 Maximum = 345 Number of Classes: Class Width: Round to the nearest whole number b. n 92 Minimum Number of Classes: - - 0.22 Maximum 1.82

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.2: Box-and-whisker Plots
Problem 2E
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Determine an appropriate number of classes and class width required to construct a grouped frequency distribution for data sets with the following values: a. n = 200 Minimum 33 Maximum Number of Classes: Class Width: Round to the nearest whole number b. n 92 Minimum Number of Classes: M 345 0.22 Maximum 1.82 SUBMIT QUESTION SAVE PROGRESS SUBMI
Transcribed Image Text:Determine an appropriate number of classes and class width required to construct a grouped frequency distribution for data sets with the following values: a. n = 200 Minimum 33 Maximum Number of Classes: Class Width: Round to the nearest whole number b. n 92 Minimum Number of Classes: M 345 0.22 Maximum 1.82 SUBMIT QUESTION SAVE PROGRESS SUBMI
a. n 200 Minimum 33 - Number of Classes: E Class Width: Round to the nearest whole number b. n = 92 Minimum Number of Classes: Class Width: Round to 2 decimal places ✓ Maximum 345 0.22 Maximum 1 SUBMIT QUESTION | 1.82 SAVE PROGRESS
Transcribed Image Text:a. n 200 Minimum 33 - Number of Classes: E Class Width: Round to the nearest whole number b. n = 92 Minimum Number of Classes: Class Width: Round to 2 decimal places ✓ Maximum 345 0.22 Maximum 1 SUBMIT QUESTION | 1.82 SAVE PROGRESS
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Step 1

From the provided information,

a) n = 200, Minimum = 33 Maximum = 345

b) n = 92, Minimum = 0.22 Maximum = 1.82

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