No.Date.Determination of Discharge Thru a SiphonVol.Q=AVt JP1P2+21=(√2) ²29+ 1² + Z2rYtrial #2trial #3t = 75t= 5sY = 340mlV: 250mLthe table below I show calculation please)1TheoreticalActual+Discharge(s)+Discharge(LIS)Formula: Q=(V1)229h = 63.5cmtrial #1t= 10sV = 490 mLcompletetrial+time(s) Volume(ml)1%0+ Difference

Given Distance = 83.5 cm = 0.835 m To find Trials Theoretical discharge Actual discharge Difference…

Answered: Determination of Discharge Thru a…

Engineering

Mechanical Engineering

Determination of Discharge Thru a Siphon Vol

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Pressure Vessels

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Question

No.
Date.
Determination of Discharge Thru a Siphon
Vol
.
Q=AV
t J
P1
P2
+21=(√2) ²
29
+ 1² + Z2
r
Y
trial #2
trial #3
t = 75
t= 5s
Y = 340ml
V: 250mL
the table below I show calculation please)
1
Theoretical
Actual
+
Discharge
(s)
+
Discharge
(LIS)
Formula: Q=
(V1)2
29
h = 63.5cm
trial #1
t= 10s
V = 490 mL
complete
trial
+
time(s) Volume
(ml)
1
%0
+ Difference

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