Design economical spacing of 10mm diameter stirrups for the beamwhich carries the factored loadsshown. Use fc' = 21 MPa and fy = 276MPa. Design shear reinforcementusing simplified calculation.Pu =150 kNw, = 80 kN/m3.00 m536 mmL= 6.00 m64 mmR1 =315 kNR2 = 315 kN300 mmPlease use NSCP 2015

The given data is: The Simply Supported Beam with following specifications. L=6 m Wu=80 KN/m Pu=150…

Answered: Design economical spacing of 10 mm…

Design economical spacing of 10 mm diameter stirrups for the beam which carries the factored loads shown. Use fc' = 21 MPa and fy = 276

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Select an A992 steel for the following beams. Use Cb = 1.0 for your calculations. Check for Shear.…

A: Given data: PL=250 lbwD=17.5 kip/ftFy=50 ksi To design the given beam, AISC code provisions can be…

Q: Hand

Q: Steel design Use A992 steel and select a W shape. The service dead load is 142 kips, and the service…

A: Given data: Service dead load=142 kips Service live load is 356 kips. Both ends are pinned and…

Q: Situation #2: A properties: Width, b = 400 mm 415 MPa rectangular beam has the following Effective…

Q: H.W -4: For the beam of sections and detail shown in Fig. find the maximum live load (PL) that the…

A: at section a-a b = 350 mmh = 600 mmfc' = 35 MPafy = 420 MPaArea of steel at bottom = 5- dia 25…

Q: Determine the maximum axial compressive service load that can be supported if the live load is twice…

A: Given:- HSS 8×4×14ASTM A500 Grade BTo find:-maximum axial compressive service load using,a)…

Q: FL AZ A C B D 2a a a The figure above shows a static indeterminate beam ABCD. The beam has a fixed…

A: Since A and C are simply supported MA and MC = 0 using three moments , 2MB ( L ) = 6a1x1L1 + 6a2x2L2…

Q: Example 2 of Method of Sections: Determine the force in member EB of the FBD of the roof truss shown…

A: To find force in member BE

Q: Determine whether the compression member shown in Figure is adequate to support the given service…

A: Given, D=110 kips L=280 kips

Q: The beam shown in Figure is laterally braced only at the ends. The 30-kip load is a service live…

A: ASD is based on the conventional stress calculation of structure with respect to the allowable…

Q: Check the beam shown for compliance with the AISCS. Lateral support is provided only at the ends,…

A: Load=70 Sin =70*(4/5) =56 KN =12.58 kipsDead Load=30% of 12.58=3.78 kipsLive…

Q: HOMEWORK-1 - 3m· For the truss shown in the figure; a) Calculate the bar forces for F=4000 kg.

A: a.given that, F=4000kg 1-2=4m 1-3=3m 2-3=42+32=5m so, we have to calculate the bar force.

Q: Knowing that the bracket AB has a uniform thickness of t, Base of theory of elasticity, determine…

Q: P Bearing plate Let the allowable stresses in the post be ost=120MPaand oco=6MPA. Compute the…

A: Solution-The given data ,σst=120MPaσco=6MpaModulus of elasticity=200GPa and For concrete 14GPaCross…

Q: snip

A: The factored axis load is Pu=1.6×28=44.8kipsthe factored transversed load and bending moment…

Q: by 늘 wo B 늘 C X

A: Given Data:Length L=6.3md=300mmbf=215mmtf=14mmtw=10mmIt is required calculate the largest intensity…

Q: Rigid beam AB is supported by three bolts at A and a pin at B. The bolts at A are in double shear…

Q: A W610 x 82 beam of A 36 steel has end reaction of 302 kN and is supported on a plate with a length…

A: Yield Strength : Yield strength of an element is a maximum stress an element or component can bear…

Q: An exterior beam along with the Axis (A) between Axes (1) and (2) is part of monolithic floor system…

A: Uniformly distributed load=50 kN/m, Ultimate uniformly distributed torque=12 kN.m/m, Fc=28 Mpa,…

Q: art 1 The simply supported beam below is initially designed to undertake a concentrated factored…

A: According to given data

Q: A W610 x 82 beam of A 36 steel has end reaction of 302 kN and is supported on a plate with a length…

A: Yield Strength :Yield strength of an element is a maximum stress an element or component can bear…

Q: a. Nominal moment capacity of the overhanging portion of the section. b. Depth of the compression…

A: Solution: Givendata: bf = 750 mm tf = 50 mm d = 750 mm bw = 350 mm Mu = 816 kN.m fc' = 20.7 Mpa fy =…

Q: A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset…

Q: 5- A beam is reinforced with Ø16 mm bars and Ø10@200 mm stirrups. If the concrete cover is 40 mm, f,…

A: Given: Diameter of reinforced bars= 16 mm Diameter of stirrups = 10 mm Spacing of stirrups= 200 mm…

Q: FIND USING ASD and LRFD A W 14 x 500 is used as a beam to support a concrete floor system. The…

A: P = 120KPa Let b be the center to center spacing between beam. So, w = P*b = 120*b

Q: Calculate area of tensile steel for a singly R.C. beam 230 mm x 380 mm size and factored moment 50…

Q: Steel Design Two channels having the given properties shown is placed at a distance of 300 mm to…

A: Compression members are structural elements primarily subjected to axial compressive forces and…

Q: The given frame is unbraced, and bending is about the x axis of each member. The axial service loads…

A: Dead load (PD) = 908 KNLive load (PL) = 1816 KNYield strength (Fy) = 350 MPa ≈ 50.76 ksiMoment of…

Q: 5 A flanged bolt coupling has ten 12-mm di ameter steel bolts on 500 mm diameter b olt circle and…

Q: Quiz: Design the reinforcement steel that necessary for the shear and torsion for the rectangular…

A: Solution; Given that; Live load=10 KN/m2Dead load =5 KN/m2fck=26MPafy=400 MPa

Q: 4. The beam shown in figure below (W 410 x 46.1) has continuous lateral support of both flanges. The…

A: As per Bartleby's guidelines we are supposed to answer only first question. Kindly repost other…

Q: Assignment 5.2 -Steel Beam Analysis P-20 kips P-? kips W 24 x 76 A992 Steel The beam carries the…

Q: For the beam(300x800mm) to carried the loads shown in the figure below,design the steel…

A: Given values: Size of beam: (Width b * Depth D) = 300 * 800 mm Span = 9 m f'c = 25 MPa fy = 414 MPa…

Q: A cantilever beam AB of length L = 6.5 ft supportsa trapezoidal distributed load of peak intensity…

A: Given:- L=6.5ft σallow =18 ksi τallow = 7.5 ksi To find:- the maximum permissible load q based…

Q: Design the flexural reinforcement of the cantilever beam shown below for the given loading and data.…

A: Solution: Design Bending Moment and Shear Force: Design Load = 1.2DL+1.6 LL=1.2(100)+1.6(70)=232kN…

Q: The simply supported beam consists of a W21 × 44 structural steel wide-flange shape [E = 29,000 ksi;…

Q: A WT305 x 41 standard steel shape is used to support the loads shown. Assume w = 56 kN/m, LAB = 1.0…

A: To Determine Maximum Compressive and tensile bending stress.

Q: For the flat plate shown in the figure below (edge beam are not used), design the hatched frame…

A: According to the question we have to design the middle and column strips of the hatched slab in N-S…

Q: ced 1.4m on centers. Use the properties of the channel section given below. Loads: (Consider all…

A: According to given data The top chords of the truss are sloped at 5H to 2V. Trusses are spaced 5m…

Q: Q14: A singly RC beam has effective dimension of 250 mm x 450 mm. It is reinforced with 3 nos 20 mm…

Q: The cantilever beam consists of a rectangular structural steel tube shape [E = 29,000 ksi; I = 1540…

Q: A rectangular post (40 mm x 80 mm) made of wood, the length of which is 5 m, supports the BC beam.…

A: Consider the given data l=6 mh=5 mF.S=1.50ζy=2…

Q: 25. Design stress is less than the ultimate strength. Truo

A: (25)Design stress is the maximum allowable stress that a material can withstand under normal…

Question

100%

Design economical spacing of 10
mm diameter stirrups for the beam
which carries the factored loads
shown. Use fc' = 21 MPa and fy = 276
MPa. Design shear reinforcement
using simplified calculation.
Pu =150 kN
w, = 80 kN/m
3.00 m
536 mm
L= 6.00 m
64 mm
R1 =315 kN
R2 = 315 kN
300 mm
Please use NSCP 2015

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

USE NSCP 2015
Can you please help me??
Topic: BEAM BEARING PLATES AND COLUMN BASE PLATES - STEEL DESIGN Please solve your Solution in a handwritten Note: It should be handwritten pleaseeee
USE NSCP 2015
PLEASE INCLUDE COMPLETE FIGURES
DETERMINE THE THE IS MAXIMUM SAFE SERVICE LIVE LOAD THAT THE BEAM CAN CAN CARRY IF SERVICE DEAD L O A D THE BEAM WEIGHT OF THE BEAM SECTION fy = 415 MPa. TOP BARS BOTTOM BARS ARE CENTER DISTANCE 12 KM/M INCLUDING AND BASED ON THE CAPACITY SHOWN. fc : 40 MPa AND ARE 6-32 mm. AND ARE - 3 - 28 mm. CENTER TO 3 BETWEEN THE USE 2015 NSCP Is 108 mm 00 0 0 300 G ט1 108 352 70. A (1 7.2m B TOP BAR LAYERS ↓ 6.7M C OM
H.W Draw S.f,B.M and elastic dliagrams for the beam Shown below by method of equntions ? 6W/m 20 KN 6m 2m 2m
USE NSCP 2015
A lightly welded steel beam shown in Figure 5 is continuously supported along its length. A downward concentrated load of 4P acts at Point C, and two downward concentrated loads P act at Points A and E. The beam with full lateral restraint is bent about its major principal x-axis. Determine the followings: a. Section type based on section slenderness; b. Effective section modulus; c. The maximum design value of P. A k B fu 6 m d tw bf 6 m tf 4P d bf tw tf = - = fyf= fyw 6 m D um * 550 mm 206 mm 6 mm 10 mm 320 MPa = 340 MPa Zx=1362985 mm³ Sx 1533750 mm³ Figure 5 Steel beam under design loads. 6 m P E
The service load bending moments on a beam are 128 kip-ft for dead load and 107 kip-ft for live load. The beam is 12 in. wide, f'c is 3000 psi and fy is 60 ksi. Determine Mu. Mt. p. R. the depth of the beam and the As of tensile reinforcing required. How many no. 8 bars or No. 10 bars would have the required As?
Pls I need answer asap, I will like it.
Question 6: Determine the LRFD design compressive strength for the shown built-up compression member composed of 2 channel (MC) sections welded to a plate. The effective buckling length of the member (KL=21 ft 2 in). Use steel with F, = 42 ksi. PL를X 12 KL = 21 A 2 in F, = 42 ksi Hint: Use parallel axis theorem to find moment of inertia about x and y axis. MC 13 x 50