Design an interior span slab of a concrete floor system with the following description: Span = 10 m Imposed dead load= 766 N/m² Live load= 4788 N/m? fc'= 27.58 MPa fy = 413.64 MPa
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- Design economical spacing of 10 mm diameter stirrups for the beam which carries the loads shown. Design shear reinforcement of prestressed beam with the following properties listed. Properties: f^c=28 MPa fy = 276MPa Aps = 800 mm² Ds = 10mm Dm = 18mm fse = 800 MPa fpu = 1500 MPa fpe = 860 MPa Pe = 250kNDesign an interior span slab of a concrete floor system with the following description: Span = 20 m Imposed dead load= 800 N/m2 Live load= 4800 N/m2 fc’= 28 MPa fy = 415 MPaA simply supported beam is reinforced with 5-p25 mm at the bottom and 2-020 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc'= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number = mm Design strength of the beam section to the nearest whole number = kN -m Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the weight of the beam) if it has a span of 6 m = kN/m (to the nearest whole number)
- A simply supported beam is reinforced with 5-ϕ25 mm at the bottom and 2-ϕ20 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc’= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number = __ mmA simply supported beam is reinforced with 5-ϕ25 mm at the bottom and 2-ϕ20 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc’= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number = mm Design strength of the beam section to the nearest whole number = kN·m Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the weight of the beam) if it has a span of 6 m = kN/m (to the nearest whole number)A simply supported beam is reinforced with 5-ϕ25 mm at the bottom and 2-ϕ20 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc’= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the weight of the beam) if it has a span of 6 m = kN/m (to the nearest whole number)
- Find the ultimate moment of resistance for the rectangular section reinforced as shown below. material strengths: Concrete Reinforcement Width of section Reinforcement fcu= 30-MPa fy:= 450-MPa b:= 280 mm d:= 510 mm d':= 50-mm 2 A, 2410-mm A's:= 628-mm 2 b A', Hi Asス F. reinforced concete structure is shown The floor framing plan oF in the figure. The beams are 280 mm wide and S20 mm deep, and the slob is 110mm thick an edditional (super impes) veight,1 and live lo ad of OTher than conerete weight, the floor subjected other to Is dead load of 3k Pa si2 k Por. Unit weight of concrete is 23.5 kN/m® le Determine the total uniform load on beam DEF and ABC axial load 20 Determme the total on columns A and B,D an) E 2Sm 티 2.Sm 6.2m 6.2mFor the following plan it is required to: 1- Design all beams for flexure and shear, where they have additional 30 kN/m distributed factored load 2- Design the columns. The concrete has a strength of 30 MPa, and the yield strength of the steel is 420 MPa. Show full calculations and neat sketches. All dimensions are in m. I 03 B2 0,3 7 B1 Wu=20 kN/m2 B1
- A two span beam subjected to shear and flexure only is reinforced as follows: SECTION @ MIDSPAN @ FACE OF SUPPORTS TOP BARS 2-∅20 mm 5-∅20 mm BOTTOM BARS 3-∅20 mm 2-∅20 mm Given: Stirrup diameter, ds = 10 mm Concrete f'c = 21 MPa Steel rebar fy = 415 MPa Stirrup fy = 275 MPa Beam size b x h = 270 mm x 450 mm Assume all bars laid out in single layer. Calculate the following: Tensile steel ratio in positive bending at midspan = __________ (in 5 decimal places) Design Moment strength of section at midspan for positive bending = ___________ kN·m (nearest whole number) Nominal Moment strength of section at face of support for negative bending = ___________ kN·m (nearest whole number)1. A two span beam subjected to shear and flexure only is reinforced as follows: SECTION: TOP BARS @ MIDSPAN: 2-⌀20mm @ FACE OF SUPPORTS: 5-⌀20mm SECTION: BOTTOM BARS @ MIDSPAN: 3-⌀20 mm @ FACE IF SUPPORTS: 2-⌀20 mm Given: Stirrup diameter, ds = 10 mm Concrete f'c = 21 MPa Steel rebar fy = 415 MPa Stirrup fy = 275 MPa Beam size b x h = 270 mm x 450 mm Assume all bars laid out in single layer. Calculate the following: a. Design Moment strength of section at midspan for positive bending = ______ kN·m (nearest whole number)Design an interior span slab of a concrete floor system with the following description: Span = 30 m Imposed dead load= 900 N/m2 Live load= 4900 N/m2 fc’= 28 MPa fy = 415 MPa Note :- Solve by ACI method