Design an efficient algorithm to solve the following scheduling problem. Provide a pseudo- code and a worst case complexity analysis for your algorithm. You are given a set of n jobs with a processing time t; and a weight w; for each job. You want to order the jobs so as to minimize the weighted some of the completion times, Żw,C, . Example: Suppose there are two jobs, the first takes time ti = 1 and has weight wi = 10, while the second takes time t2 = 3 and has weight w2 = 2. Then doing job 1 first would yield a weighted completion time of 1Ox1 + 2x4 = 18, while doing job 2 first yields the larger weighted completion time of 10x4 + 2x3 = 46.

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7th Edition
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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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1. Design an efficient algorithm to solve the following scheduling problem. Provide a pseudo-
code and a worst case complexity analysis for your algorithm.
You are given a set of n jobs with a processing time t; and a weight w; for each job. You
want to order the jobs so as to minimize the weighted some of the completion times,
Žw,C, .
i=1
Example: Suppose there are two jobs, the first takes time ti = 1 and has weight wi = 10,
while the second takes time t2 = 3 and has weight w2 = 2. Then doing job 1 first would yield
a weighted completion time of 10x1 + 2x4 = 18, while doing job 2 first yields the larger
weighted completion time of 10x4 + 2x3 = 46.
Transcribed Image Text:1. Design an efficient algorithm to solve the following scheduling problem. Provide a pseudo- code and a worst case complexity analysis for your algorithm. You are given a set of n jobs with a processing time t; and a weight w; for each job. You want to order the jobs so as to minimize the weighted some of the completion times, Žw,C, . i=1 Example: Suppose there are two jobs, the first takes time ti = 1 and has weight wi = 10, while the second takes time t2 = 3 and has weight w2 = 2. Then doing job 1 first would yield a weighted completion time of 10x1 + 2x4 = 18, while doing job 2 first yields the larger weighted completion time of 10x4 + 2x3 = 46.
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