Design a tied (rectangular) column to support a service dead axial load of D = 300,000 lbf and a servicelive load of L = 480,000 lbf. Use f ‘c = 4,000 lbf/in2; fy = 60,000 lbf/in2. Check Load Combination 2 only.

2 2a. 2b. 2c. The designed axially loaded column is W 8 x 13 with the following data: kg/m |d=202.05 mm ry=21.41 mm Ag=2477 sq mm Wt. = 19 rx = 81.53 mm Assuming that W 8 x 13 is not available which of the following shall be the best option as replacement? Why? Use: Fy=248 MPa: E=200,000 MPa W8x15 Ag=2865 sq mm d=205.99 mm rx=83.57 mm Wt=22 kg/m Wt=24 kg/m W 6 x 16 Ag=3058 sq mm d=152.15 mm rx=65.02 mm W5X 16 Ag=3019 sq mm Wt = 24 kg/m d=127.25 mm rx = 54.10 mm expla'n briefly your cho'ce. (transform your comparative analys's 'nto a narat've form to support your cho'ce) ry=22.25 mm ry=37.08 mm ry=32.26 mm

1%9. l. In. • f 10 Y:- quiz2.pdf > Quiz: Design the reinforcement steel that necessary for the shcar and torsion for the rectangular cantilever beam shown in figure. Use for stirrups (o12) and let f.=25 MPa, f-400 MPa, dead load (5 kN/m?) and live load (10 kN/m), take into account the self-weight of beam. All dimensions in (mm) 1000 800 3000 300 Cnand TEXTEDT II

Situation #2: A rectangular beam has the following properties: Width, b = 400 mm 415 MPa Effective depth, d = 620 mm 22 MPa Tension bars, 10 pcs 28-mm-diameter Compression bars, 3 pcs 25-mm-diamter d' = 70 mm fy= = fc' = Determine the design strength of the beam and the safe live load if the service dead load is 320 kN.m

The floor system shown below supports a uniform dead load of 100 lb/ft² and a uniform live load of 40 lb/ft?. Draw the loads with magnitudes on the following structural members: а) BI b) В2 с) ВЗ d) B4 e) Gl f) G2 g) G4 6 @ 7' = 42' C4 G1 B3 B2 2 @ 15' = 30' G4 G3 G2 BT 5 @ 6' = 30' 42' 36' For the same floor plan shown above and assuming the same floor loads and that the building consists of four floors, determine the following: a) The dead load on column Cl in the first floor. b) The live load on column C2 in the second floor. Consider live load reduction. c) The sum of the dead plus live loads on column C3 in the third floor. Consider live load reduction. OT

learn Determine the reaction forces for beams B-1, B-2, and B-3. Column A Column B Girder G-1 open Girder G-2 L1 L1 L1 • Live load = 30 psf • Dead load: (1) Slab = 50 psf, (2) Deck = 5 psf, (3) Mechanical equipment = 13 psf, (4) Suspended ceiling = 8 psf, (5) Beam = 25 Ib/ft, (6) Girder 35 lb/ft • Beam and Girder spacing: : (1) L1 = 14 ft, (2) L2 = 10 ft, (3) L3 = 10 ft Please round to the nearest one. Reaction force for Beam B-1 (one side only) = Ibs Reaction force for Beam B-2 (one side only) = Ibs Reaction force for Beam B-3 (open side) = Ibs Reaction force for Beam B-3 (Girder G-1 side) = Ibs MacBook Air II F8 F1 F2 F3 F4 F5 F6 F7 $ % & * 2 3 4 5 6 7 8 Beam B-1 Beam B-2 Beam B-3 Beam B-4 L3 L2

A Assignment 1 @p=1.5 k/ft @=2.0 k/ft 20 ft f=5,000 psi f₂ = 60,000 psi Including beam weight B PD=5 k P₁= 8 k 8 ft h Design Beam ABC: The beam carries the concentrated loads at the end of the overhang and the distributed loads across the span as shown

Determine the design strength of the beam(properties given below) and the safe service live load if the service dead load is 320 kN.m.Use f'c =22 Mpa and fy=415 MPa. given properties: b=400 mm d'=70 mm d=620 mm As=10-28 mm A's=3-25 mm bars hello please answer this thanks ☺️

1- Design a rectangular section for the simply supported beam shown in the figure. The dead load wp = 2 k/ft, and live load w, = 1.4 k/ft. The span of the beam 1-25 ft. Beam weight is not included in the given loads. Assume b= 14 in. Use f = 4000 psi and fy = 60000 psi. WD and WL l 777

A concrete circular column with a radius of 350mm has f'c-25 MPa and is braced against sidesway. The column is assumed to be pinned on both ends with an unsupported length is 6.1meters. The column is subjected to the following service loads: Axial Dead Load =350 kN Axial Live Load=480 kN Moment due to Dead Load on the top of the column = 125 kN-m Moment due to Dead Load on the bottom of the column = 60 kN-m Moment due to Live Load on the top of the column = 122 kN-m Moment due to Live Load on the bottom of the column = 75 kN-m. If the moments bent the column in a singular curve, determine the following: 1. Critical Load on the column, kN 2. Moment Magnifying factor 3. Design Moment of the column, kN-m.