Please solve it in Java... Design a class named QuadraticEquation for solving a quadratic equation which isof the form ax²+bx+c=0.QuadraticEquation- a: double- b: double- c: double+ QuadraticEquation(a: double, b: double, c: double)- getDiscriminant(): double+ evaluateDiscriminant(): void+ getRoot1(): double+ getRoot2(0: double+ toString(): StringThe class should contain:Private data fields a , b , and c that represent three coefficients.• A single constructor for the arguments for a , b, and c.A private method named getDiscriminant() that returns the discriminant,which is the value of b?-4 ac.A public method named evaluateDiscriminant() which prints out thefollowing information using the value obtained from getDiscriminant():o getDiscriminant() > 0, "Two distinct solutions"getDiscriminant()o getDiscriminant() < 0, “No real solutions"The public methods named getRoot1() and getRoot2() return the tworoots of the equation. They return the following, respectively:= 0, "One unique solution"-b + Vb - 4ac-b –VB - 4acand r2 =2a2aHowever, if no real solutions exist, print out the message "Not possible tocalculate solutions since discriminant is negative". Youmay have to return an arbitrary value in this case.The toString() method returns the details in the following tabular format:Faculty: SAS3CSE215L1Coefficient | Value| value of a upto 3 decimal placesab| value of b upto 3 decimal places| value of c upto 3 decimal placesIn your driver class,construct three objects of QuadraticEquation. Use Scanner class to getthe values of the coefficients for each object.Call the evaluateDiscriminant() method on each of the objects.Then, call the getRoot1() and getRoot2() methods on each of theobjects and display the results.||

import java.util.Scanner; public class Main{ public static void main(String[] args) { Scanner…

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Design a class named QuadraticEquation for solving a quadratic equation which is of the form ax²+bx+c=0.

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Question

Please solve it in Java...

Design a class named QuadraticEquation for solving a quadratic equation which is
of the form ax²+bx+c=0.
QuadraticEquation
- a: double
- b: double
- c: double
+ QuadraticEquation(a: double, b: double, c: double)
- getDiscriminant(): double
+ evaluateDiscriminant(): void
+ getRoot1(): double
+ getRoot2(0: double
+ toString(): String
The class should contain:
Private data fields a , b , and c that represent three coefficients.
• A single constructor for the arguments for a , b, and c.
A private method named getDiscriminant() that returns the discriminant,
which is the value of b?-4 ac.
A public method named evaluateDiscriminant() which prints out the
following information using the value obtained from getDiscriminant():
o getDiscriminant() > 0, "Two distinct solutions"
getDiscriminant()
o getDiscriminant() < 0, “No real solutions"
The public methods named getRoot1() and getRoot2() return the two
roots of the equation. They return the following, respectively:
= 0, "One unique solution"
-b + Vb - 4ac
-b –
VB - 4ac
and r2 =
2a
2a
However, if no real solutions exist, print out the message "Not possible to
calculate solutions since discriminant is negative". You
may have to return an arbitrary value in this case.
The toString() method returns the details in the following tabular format:
Faculty: SAS3
CSE215L
1
Coefficient | Value
| value of a upto 3 decimal places
a
b
| value of b upto 3 decimal places
| value of c upto 3 decimal places
In your driver class,
construct three objects of QuadraticEquation. Use Scanner class to get
the values of the coefficients for each object.
Call the evaluateDiscriminant() method on each of the objects.
Then, call the getRoot1() and getRoot2() methods on each of the
objects and display the results.
||

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