Describe the sampling distribution of p. Assume the size of the population is 20,000. n = 200, p = 0.2

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Describe the sampling distribution of p. Assume the size of the population is 20,000. n = 200, p = 0.2
### Sampling Distribution of Proportion

**Context:**
We are examining the sampling distribution of the sample proportion \(\hat{p}\). The given conditions include a sample size \(n = 200\) and a population proportion \(p = 0.2\). The population size is 20,000.

**Question:**
Choose the phrase that best describes the shape of the sampling distribution of \(\hat{p}\):

1. **A.** Approximately normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\).
2. **B.** Approximately normal because \(n \leq 0.05N\) and \(np(1-p) < 10\).
3. **C.** Not normal because \(n \leq 0.05N\) and \(np(1-p) < 10\).
4. **D.** Not normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\).

**Solution Steps:**

1. **Sample Size Condition:** 
   Check if the sample size \(n\) is less than or equal to 5% of the population size \(N\): 
   \[
   n = 200, \quad N = 20,000 \quad \Rightarrow \quad n \leq 0.05 \times 20,000
   \]
   Therefore, \(200 \leq 1,000\), which satisfies the condition.

2. **Normal Approximation Condition:** 
   Check if the product \(np(1-p) \geq 10\):
   \[
   np(1-p) = 200 \times 0.2 \times (1 - 0.2) = 200 \times 0.2 \times 0.8 = 32
   \]
   Clearly, \(32 \geq 10\), which satisfies the condition for a normal approximation.

**Answer:** The correct choice is **A.** Approximately normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\).

**Determine the Mean and Standard Deviation of \(\hat{p}\):**

- **Mean of the Sampling Distribution (\(\mu_{\hat{p}}\)):**
  \
Transcribed Image Text:### Sampling Distribution of Proportion **Context:** We are examining the sampling distribution of the sample proportion \(\hat{p}\). The given conditions include a sample size \(n = 200\) and a population proportion \(p = 0.2\). The population size is 20,000. **Question:** Choose the phrase that best describes the shape of the sampling distribution of \(\hat{p}\): 1. **A.** Approximately normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\). 2. **B.** Approximately normal because \(n \leq 0.05N\) and \(np(1-p) < 10\). 3. **C.** Not normal because \(n \leq 0.05N\) and \(np(1-p) < 10\). 4. **D.** Not normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\). **Solution Steps:** 1. **Sample Size Condition:** Check if the sample size \(n\) is less than or equal to 5% of the population size \(N\): \[ n = 200, \quad N = 20,000 \quad \Rightarrow \quad n \leq 0.05 \times 20,000 \] Therefore, \(200 \leq 1,000\), which satisfies the condition. 2. **Normal Approximation Condition:** Check if the product \(np(1-p) \geq 10\): \[ np(1-p) = 200 \times 0.2 \times (1 - 0.2) = 200 \times 0.2 \times 0.8 = 32 \] Clearly, \(32 \geq 10\), which satisfies the condition for a normal approximation. **Answer:** The correct choice is **A.** Approximately normal because \(n \leq 0.05N\) and \(np(1-p) \geq 10\). **Determine the Mean and Standard Deviation of \(\hat{p}\):** - **Mean of the Sampling Distribution (\(\mu_{\hat{p}}\)):** \
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