Derive the shear force equation,bending moment equation for the beam shown. Neglect the weight of the beam. A -6 ft- B Determine the following: 26. Reaction support at point B. O a. 1350 lb (Upward Direction) O b. 1380 lb(Downward Direction) c. 1400 lb (Upward Direction) d. 1420 lb (Downward Direction) Û 200 lb/ft CA 1200 lb ft 4f-4ft- 27. Reaction support at point D. * O a. 600 lb (Upward Direction) O 700 lb (Downward Direction) c. 800 lb (Upward Direction) O d. 900 lb (Downward Direction) 28. Centroid of the triangular load. * O a. 588 lb (Downward Direction) O b. 598 lb (Upward Direction) O c. 600 lb(Downward Direction) Od. (Upward Direction) D

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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b. 8 feet
c. 10 feet
លី
O d. 12 feet
30. Bending moment equation for segment AB.
O a.-5.40 psf X cube
Ob. 5.45 psf X cube
O c.-5.55 psf X cube
Od. 6.55 psf X cube
31. Shear force equation for segment BC. *
Oa. 2000 lb-200 lb/ft (X)
Ob. 2100 lb-300 lb/ft (X)
O c. 2150 lb-300 lb/ft (X)
O d. 3000 lb-200 lb/ft (X)
33. The distance between point A and the shear force VAB=0 ★
Oa. 6 feet
3
Bending moment equation for segment BC.
O a. 2000 lb(x)-100 lb/ft (X squared) - 9600 lb-ft
O b. 2100 lb(x)-120 lb/ft (X squared)-9700 lb-ft
O c. 21500 lb(X)-200 lb/ft (X squared) - 9800 lb-ft
O d. 3000 lb(X)-200 lb/ft (X squared) - 9850 lb-ft
34. The degree of bending moment equations for segments AB and BC.
O a. 1st degree and 2rd degree
Ob. 3rd degree and 2nd degree
Oc. 2nd degree and 3rd degree
Od. None of the above.
Transcribed Image Text:b. 8 feet c. 10 feet លី O d. 12 feet 30. Bending moment equation for segment AB. O a.-5.40 psf X cube Ob. 5.45 psf X cube O c.-5.55 psf X cube Od. 6.55 psf X cube 31. Shear force equation for segment BC. * Oa. 2000 lb-200 lb/ft (X) Ob. 2100 lb-300 lb/ft (X) O c. 2150 lb-300 lb/ft (X) O d. 3000 lb-200 lb/ft (X) 33. The distance between point A and the shear force VAB=0 ★ Oa. 6 feet 3 Bending moment equation for segment BC. O a. 2000 lb(x)-100 lb/ft (X squared) - 9600 lb-ft O b. 2100 lb(x)-120 lb/ft (X squared)-9700 lb-ft O c. 21500 lb(X)-200 lb/ft (X squared) - 9800 lb-ft O d. 3000 lb(X)-200 lb/ft (X squared) - 9850 lb-ft 34. The degree of bending moment equations for segments AB and BC. O a. 1st degree and 2rd degree Ob. 3rd degree and 2nd degree Oc. 2nd degree and 3rd degree Od. None of the above.
Derive the shear force equation,bending moment equation for the beam
shown. Neglect the weight of the beam.
6 ft
B
Determine the following:
26. Reaction support at point B.
O a. 1350 lb (Upward Direction)
Ob. 1380 lb(Downward Direction)
Oc. 1400 lb (Upward Direction)
Od. 1420 lb (Downward Direction)
Û
200 lb/ft
O
C
1200 lb ft
4f-4ft -
27. Reaction support at point D. *
O a. 600 lb (Upward Direction)
Ob. 700 lb (Downward Direction)
c. 800 lb (Upward Direction)
Od. 900 lb (Downward Direction)
28. Centroid of the triangular load. *
a. 588 lb (Downward Direction)
Ob. 598 lb (Upward Direction)
Oc. 600 lb(Downward Direction)
Od. (Upward Direction)
D
29. Shear force equation for segment AB.
a.-16.65 psf X squared
Ob. 16.65 psf X squared
Oc.-16.75 psf X squared
O d. 16.75 psf X squared
Transcribed Image Text:Derive the shear force equation,bending moment equation for the beam shown. Neglect the weight of the beam. 6 ft B Determine the following: 26. Reaction support at point B. O a. 1350 lb (Upward Direction) Ob. 1380 lb(Downward Direction) Oc. 1400 lb (Upward Direction) Od. 1420 lb (Downward Direction) Û 200 lb/ft O C 1200 lb ft 4f-4ft - 27. Reaction support at point D. * O a. 600 lb (Upward Direction) Ob. 700 lb (Downward Direction) c. 800 lb (Upward Direction) Od. 900 lb (Downward Direction) 28. Centroid of the triangular load. * a. 588 lb (Downward Direction) Ob. 598 lb (Upward Direction) Oc. 600 lb(Downward Direction) Od. (Upward Direction) D 29. Shear force equation for segment AB. a.-16.65 psf X squared Ob. 16.65 psf X squared Oc.-16.75 psf X squared O d. 16.75 psf X squared
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