Derive the expression for electric potential across the axial line
Q: Given is potential V(x,y,z) = 2x2+5y2+6z2-3xyz. where V is in volts and x, y, z are in meters. Find…
A:
Q: 4.0cm Q. 2: Point charges q1=+8.0µC, q2=-2.0µC and q3= +3.0µC are placed at the vertices of a right-…
A:
Q: When drawing equal potential lines in a parallel plate, can you draw a straight line with arrows ?
A: When visualizing the electric field and potential in a parallel plate capacitor, it's essential to…
Q: A tiny pith ball of mass 5.0 x 10-4kg is suspended by a light thread of negligible mass. The ball is…
A:
Q: Four point charges each of charge 2.50×10^-5, are located on c- and y-axes, one at each of the…
A: Electric potential at the origin V=∑i=14kqiri=kq1r1+q2r2+q3r3+q4r4=kq1r1+1r2+1r3+1r4
Q: rge q3 between gi and nC is to be placed on the z-axis 92. (Take as zero the potential energy of the…
A:
Q: Determine the electric potential due to a uniformly charged ring (total charge Q = 6.0 nC and radius…
A:
Q: A charge Q is distributed uniformly around the perimeter of a ring of radius R. Determine the…
A: The electric potential is defined as the potential energy per unit charge. The electric potential is…
Q: A parallel-plate capacitor has a capacitance of 680 pF, a plate area of 580 cm², and a mică…
A: Given that: The capacitance is C=680 pF= 680×10-12 F The area of the plate is A=580 cm2=580×10-4 m2…
Q: onsider a positive charge q1=+Q placed at the origin and a negative charge q2=-3Q placed at a…
A:
Q: Two point charges are placed on the ?-axis: 0.500 μC at ?=0 and −0.200 μC at ?=20.0 cm. At what…
A: Given the charges q1=0.500μC at x=0and q2=-0.200μC at x=20.0cm let at point x1 on the x-axis the…
Q: (a) The electric potential in a region is given by the equation: V V(x, y) = (2.00 × 105 —5)x³yz +…
A:
Q: Find the components of the electric field at the point (x, y, z) = (3,4,5) of space if the electric…
A:
Q: (a) What is the electric potential of each sphere? r = 6.00 m: r = 2.00 cm: (b) What is the electric…
A: Given data The combined magnitude charge of the charge is Q1+Q2=59 μC........(1) The radius of…
Q: An electric dipole consists of two charges of equal magnitude and opposite sign separated by a…
A:
Q: If we double our distance from a charged particle, determine what happens to (a) the potential…
A:
Q: In the figure below, determine the point (other than infinity) at which the electric field is zero.…
A: Given: q1 = -1.65 μCq2 = 6.90 μC To Find: The distance of the point at which the electric field is…
Q: A parallel-plate capacitor has circular plates of 5.05 cm radius and 1.40 mm separation. (a)…
A: Given Data:- Radius of the parallel plate capacitor is r=5.05 cm=5.05 cm×1 m100 cm=0.0505 m…
Q: Which of the following statements is true about the magnitude of the net electric field E and the…
A:
Q: When we have a uniformly charged ring, if we evaluate the electric potential at the center of the…
A: When we have a uniformly charged ring, if we evaluate the electric potential at the center of the…
Q: Electric Potential is given by V=6x-8xy2-8y+6yz-4z2 then the electric force acting on 2 Coulomb…
A:
Q: Sketch the electric field lines of the parallel plate capacitor and the variation of the following…
A: Given Sketch the electric field lines of the parallel plate capacitor and the variation of the…
Derive the expression for electric potential across the axial line and show that electric potential due to quadrupole along axis is double than that of electric potential along equatorial line in magnitude at equal distance "r" from the center of quadrupole?
Step by step
Solved in 2 steps with 1 images
- The electric potential from an elementary electric dipole located at the origin is given by the expression Þ(r) = p'r/(4TE,r³) where p is the electric dipole moment vector. Show that the corresponding electric field is given by the expression E = -VO = (3 p'r-hat r-hat - p)/(4tE,r³) where r-hat is the unit vector in the direction of the vector r.Suppose that three points are set at equal (large) distances r from the center of the dipole in Fig. below: Point a is on the dipole axis above the positive charge, point b is on the axis below the negative charge, and point c is on a perpendicular bisector through the line connecting the two charges. Rank the points according to the electric potential of the dipole there, greatest (most positive) first.Q20))Calculate the electrical potential at a point 12 cm from the center of a properly charged disc with surface charge density σ = 1.2 nC / m² and radius 5 cm.A) 0.467 VB) 0.678 VC) 0.231 VD) 0.325 VE) 0.538 V