Derive Egns 4.5-4.7 (using Egn 4.4) and comment on the results when A all the derivation steps in details. Short-cut will deduct your mark. What is relation between Eans 4.5 and 4.6? Write about the physical significance of the term of Eans 4.5-4.7. 1. S AGm - 0,ln 91 + Opm In opmt P1PpmXipm Npm %3D yFH Eqn 4.4 RT (AGm a2 RT „FH Xsp 1pm +: \P1 NpmPpm, O gives: Eqn 4.5 112

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Chapter1: Chemical Foundations
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Derive Egns 4.5–4.7 (using Egn 4.4) and comment on the results when N = 1. Show
all the derivation steps in details. Short-cut will deduct your mark. What is the
relation between Eans 4.5 and 4.6? Write about the physical significance of the LH
term of Egns 4.5-4.7.
AGm
Opm In opm+ P1PpmXipm
Npm
yFH
= 7,In o1 +
RT
Eqn 4.4
(AGm
RT
0 gives:
yFH
Xsp 1pm
Eqn 4.5
\91 ' Npm9pm/
pm
(AG,
2
= 0 gives:
„FH
Xc ipm
RT
Npm " (Npm))
1/2
Eqn 4.6
1
d
FH
Egn 4.7
(rim) = 0
dopm
Pc pm
%3!
1/2
1+ (Npm)"2
Transcribed Image Text:Derive Egns 4.5–4.7 (using Egn 4.4) and comment on the results when N = 1. Show all the derivation steps in details. Short-cut will deduct your mark. What is the relation between Eans 4.5 and 4.6? Write about the physical significance of the LH term of Egns 4.5-4.7. AGm Opm In opm+ P1PpmXipm Npm yFH = 7,In o1 + RT Eqn 4.4 (AGm RT 0 gives: yFH Xsp 1pm Eqn 4.5 \91 ' Npm9pm/ pm (AG, 2 = 0 gives: „FH Xc ipm RT Npm " (Npm)) 1/2 Eqn 4.6 1 d FH Egn 4.7 (rim) = 0 dopm Pc pm %3! 1/2 1+ (Npm)"2
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