Derive Egns 4.5–4.7 (using Egn 4.4) and comment on the results when N = 1. Showall the derivation steps in details. Short-cut will deduct your mark. What is therelation between Eans 4.5 and 4.6? Write about the physical significance of the LHterm of Egns 4.5-4.7.AGmOpm In opm+ P1PpmXipmNpmyFH= 7,In o1 +RTEqn 4.4(AGmRT0 gives:yFHXsp 1pmEqn 4.5\91 ' Npm9pm/pm(AG,2= 0 gives:„FHXc ipmRTNpm " (Npm))1/2Eqn 4.61dFHEgn 4.7(rim) = 0dopmPc pm%3!1/21+ (Npm)"2

Answered: Image /qna-images/answer/b6d29401-dabb-4628-a0cd-d08d13792db2.jpg

Derive Egns 4.5-4.7 (using Egn 4.4) and comment on the results when A all the derivation steps in details. Short-cut will deduct your mark. What is relation between Eans 4.5 and 4.6? Write about the physical significance of the term of Eans 4.5-4.7. 1. S AGm - 0,ln 91 + Opm In opmt P1PpmXipm Npm %3D yFH Eqn 4.4 RT (AGm a2 RT „FH Xsp 1pm +: \P1 NpmPpm, O gives: Eqn 4.5 112

Derive Egns 4.5-4.7 (using Egn 4.4) and comment on the results when A all the derivation steps in details. Short-cut will deduct your mark. What is relation between Eans 4.5 and 4.6? Write about the physical significance of the term of Eans 4.5-4.7. 1. S AGm - 0,ln 91 + Opm In opmt P1PpmXipm Npm %3D yFH Eqn 4.4 RT (AGm a2 RT „FH Xsp 1pm +: \P1 NpmPpm, O gives: Eqn 4.5 112

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Derive Egns 4.5–4.7 (using Egn 4.4) and comment on the results when N = 1. Show
all the derivation steps in details. Short-cut will deduct your mark. What is the
relation between Eans 4.5 and 4.6? Write about the physical significance of the LH
term of Egns 4.5-4.7.
AGm
Opm In opm+ P1PpmXipm
Npm
yFH
= 7,In o1 +
RT
Eqn 4.4
(AGm
RT
0 gives:
yFH
Xsp 1pm
Eqn 4.5
\91 ' Npm9pm/
pm
(AG,
2
= 0 gives:
„FH
Xc ipm
RT
Npm " (Npm))
1/2
Eqn 4.6
1
d
FH
Egn 4.7
(rim) = 0
dopm
Pc pm
%3!
1/2
1+ (Npm)"2

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