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Derivation of the Clapeyron Eq. Please recall that earlier this semester, we began with the Clapeyron Eq. and derived the Clausius-Clapeyron Eq. At the time we said we said that we would derive the Clapeyron Eq. from First Principles. a. Please write the 4th Fundamental Property Relation for a single phase, pure substance. b. Now, please consider two phases of a single, pure substance that are in equilibrium with each other. We will designate the phases a-phase and B-phase. Although the system is 2-phase, each phase is single phase. Therefore, we can write the 4th Fundamental Property Relation for each phase. c. Equilibrium means that T = Tat andP = Psat. d. Recall that at in equilibrium dğa = dğß which leads to ma dDsat aa dT sat B dDsat B AT sat

Derivation of the Clapeyron Eq. Please recall that earlier this semester, we began with the Clapeyron Eq. and derived the Clausius-Clapeyron Eq. At the time we said we said that we would derive the Clapeyron Eq. from First Principles. a. Please write the 4th Fundamental Property Relation for a single phase, pure substance. b. Now, please consider two phases of a single, pure substance that are in equilibrium with each other. We will designate the phases a-phase and B-phase. Although the system is 2-phase, each phase is single phase. Therefore, we can write the 4th Fundamental Property Relation for each phase. c. Equilibrium means that T = Tat andP = Psat. d. Recall that at in equilibrium dğa = dğß which leads to ma dDsat aa dT sat B dDsat B AT sat

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Solve part E and Part F only
1. Derivation of the Clapeyron Eq. Please recall that earlier this semester, we began with the Clapeyron Eq. and derived the Clausius-Clapeyron Eq. At the time we said we said that we would derive the Clapeyron Eq. from First Principles. a. Please write the 4th Fundamental Property Relation for a single phase, pure substance. b. Now, please consider two phases of a single, pure substance that are in equilibrium with each other. We will designate the phases a-phase and B-phase. Although the system is 2-phase, each phase is single phase. Therefore, we can write the 4th Fundamental Property Relation for each phase. c. Equilibrium means that T = Tsat and P= Psat d. Recall that at in equilibrium dğª = dğb which leads to DadPsat – 5a dT sat ob dpsat – 56 dT sat e. Divide through by dTsat and collect terms by volume and entropy. f. Let's consider the transition from a-phase and B-phase, that is the "aß" phase transition. (We could just as easily consider the "Ba" phase transition. The result would be the same.) Please show that dpsat (5ª – ff). = sa -. dTsat = -Abaß =-Asaß
Transcribed Image Text:1. Derivation of the Clapeyron Eq. Please recall that earlier this semester, we began with the Clapeyron Eq. and derived the Clausius-Clapeyron Eq. At the time we said we said that we would derive the Clapeyron Eq. from First Principles. a. Please write the 4th Fundamental Property Relation for a single phase, pure substance. b. Now, please consider two phases of a single, pure substance that are in equilibrium with each other. We will designate the phases a-phase and B-phase. Although the system is 2-phase, each phase is single phase. Therefore, we can write the 4th Fundamental Property Relation for each phase. c. Equilibrium means that T = Tsat and P= Psat d. Recall that at in equilibrium dğª = dğb which leads to DadPsat – 5a dT sat ob dpsat – 56 dT sat e. Divide through by dTsat and collect terms by volume and entropy. f. Let's consider the transition from a-phase and B-phase, that is the "aß" phase transition. (We could just as easily consider the "Ba" phase transition. The result would be the same.) Please show that dpsat (5ª – ff). = sa -. dTsat = -Abaß =-Asaß
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