Can someone explain the output of this pseudocode code to me?Also S(n) is set_x() and P() is print_x()I will rate! sider the following pseudo code:x : integer : =1y: integer : =2procedure set_x(n: integer)X:=nprocedure print_x ( )write_integer (x)procedure addx :=x+yprocedure fun(A: function; n: integer)y: integer : = 3if y>nelseadd ()procedure foo(S, P: function; n: integer)x : integer := 5if n in {1,3}elseA()elseset_x(n)S(n)if n in {1, 2}print_x()P()fun(add, n)set_x(0); foo(set_x, print_x, 1); print_xset_x(0); foo(set_x, print_x, 2); print_xset_x(0); foo(set_x, print_x, 3); print_xa. what will the program print if the language uses static scopingb. if the language uses dynamic scoping, what will the programshallow binding?c. if the language uses dynamic scoping, what will the programbinding?

The scope of a variable is established at compile time with static scoping. The compiler searches…

der the following pseudo code: x : integer : =1 y: integer :=2 procedure set_x(n: integer) X: n procedure print_x () write_integer (x) procedure add x :=x+y procedure fun(A: function; n: integer) y: integer : = 3 if y>n A() add () procedure foo(S, P: function; n: integer) x : integer := 5 if n in {1, 3} else else set_x(n) S(n) if n in {1, 2} else print_x() P() fun(add, n) set_x(0); foo(set_x, print_x, 1); print_x set_x(0); foo(set_x, print_x, 2); print_x set_x(0); foo(set_x, print_x, 3); print_x a. what will the program print if the language uses static scoping b. if the language uses dynamic scoping, what will the program shallow binding?

der the following pseudo code: x : integer : =1 y: integer :=2 procedure set_x(n: integer) X: n procedure print_x () write_integer (x) procedure add x :=x+y procedure fun(A: function; n: integer) y: integer : = 3 if y>n A() add () procedure foo(S, P: function; n: integer) x : integer := 5 if n in {1, 3} else else set_x(n) S(n) if n in {1, 2} else print_x() P() fun(add, n) set_x(0); foo(set_x, print_x, 1); print_x set_x(0); foo(set_x, print_x, 2); print_x set_x(0); foo(set_x, print_x, 3); print_x a. what will the program print if the language uses static scoping b. if the language uses dynamic scoping, what will the program shallow binding?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Can someone explain the output of this pseudocode code to me?

Also S(n) is set_x() and P() is print_x()

I will rate!

sider the following pseudo code:
x : integer : =1
y: integer : =2
procedure set_x(n: integer)
X:=n
procedure print_x ( )
write_integer (x)
procedure add
x :=x+y
procedure fun(A: function; n: integer)
y: integer : = 3
if y>n
else
add ()
procedure foo(S, P: function; n: integer)
x : integer := 5
if n in {1,3}
else
A()
else
set_x(n)
S(n)
if n in {1, 2}
print_x()
P()
fun(add, n)
set_x(0); foo(set_x, print_x, 1); print_x
set_x(0); foo(set_x, print_x, 2); print_x
set_x(0); foo(set_x, print_x, 3); print_x
a. what will the program print if the language uses static scoping
b. if the language uses dynamic scoping, what will the program
shallow binding?
c. if the language uses dynamic scoping, what will the program
binding?

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