density of the infinite sheet o = -44pC/m^2 , radius of the solid sphere R = 2.7m, radius of the Gaussian sphere r= 5.4m value of h = 1.35m. (here 1pC means pico coulomb charge that is, 10^-12 C.) %3D %3D Step 1: Consider the infinite sheet only for this step. k) Find the net flux through the Gaussian sphere of radius r due to infinite sheet only.(N.m^2/C)
density of the infinite sheet o = -44pC/m^2 , radius of the solid sphere R = 2.7m, radius of the Gaussian sphere r= 5.4m value of h = 1.35m. (here 1pC means pico coulomb charge that is, 10^-12 C.) %3D %3D Step 1: Consider the infinite sheet only for this step. k) Find the net flux through the Gaussian sphere of radius r due to infinite sheet only.(N.m^2/C)
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Use the following constants if necessary. Coulomb constant, k = 8.987×10^9 N⋅ m^2/C^2 . Vacuum permittivity, ϵ0 = 8.854×10^−12 F/m . Magnitude of the Charge of one electron, e = −1.60217662×10^−19 C . Mass of one electron, me = 9.10938356×10^−31 kg . Unless specified otherwise, each symbol carries their usual meaning. For example, μC means microcoulomb .
Solve k. Please solve correctly & provide the answer in(N.m^2/C).
Transcribed Image Text:An infinite sheet lie on the xz plane and z axis points outward.
A solid non-conducting sphere of radius R is placed at h+r
distance away from the infinite sheet. Use the following values of
these quantities charge density of sphere p = 38 pC/m^3, charge
density of the infinite sheet o = -44pC/m^2 , radius of the solid
sphere R = 2.7m, radius of the Gaussian sphere r= 5.4m value
of h = 1.35m. (here 1pC means pico coulomb charge that is,
10^-12 C.)
%3D
Step 1: Consider the infinite sheet only for this step.
k) Find the net flux through the Gaussian sphere of radius r due
to infinite sheet only.(N.m^2/C)
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