Delawarium, which has an FCC crystal structure. The following information is known about Delawarium: Symbol: De Atomic Number #29 Atomic Weight: 63.55 (AMU) Density at 20 degrees C: 8.96 g/cm3 (Measured) Atomic Radius: 0.128 nm Ionic Radius: 0.096 nm -- (a) Determine the unit edge length, a, in nm using the atomic radius. -- (b) Calculate the theoretical density and compare it to the measured density provided. -- (c) Given the measured and theoretical densities, would it be possible to use density to tell if there was 0.67 atomic % of Ni (an FCC metal – with a metallic atomic radius of 0.125 nm and ionic radius of 0.069 nm and AW of 58.69 AMU) in solid solution? Give at least two bullet point reasons to support your answer.
Delawarium, which has an FCC crystal structure. The following information is known about Delawarium:
Symbol: De
Atomic Number #29
Atomic Weight: 63.55 (AMU)
Density at 20 degrees C: 8.96 g/cm3 (Measured)
Atomic Radius: 0.128 nm
Ionic Radius: 0.096 nm
--
(a) Determine the unit edge length, a, in nm using the atomic radius.
--
(b) Calculate the theoretical density and compare it to the measured density provided.
--
(c) Given the measured and theoretical densities, would it be possible to use density to tell if there was 0.67 atomic % of Ni (an FCC metal – with a metallic atomic radius of 0.125 nm and ionic radius of 0.069 nm and AW of 58.69 AMU) in solid solution? Give at least two bullet point reasons to support your answer.
Delawarium crystallizes into a FCC structure, having an atomic radius of 0.128 nm.
In a FCC crystal structure, the unit cell consists of a total of 4 atoms, half an atom at each of the 6 faces of the cube and one eight of an atom at each of the 8 corners, making a total of 4 atoms.
In a FCC crystal structure, the edge length of the cubic cell is related to the atomic radius of the atoms within the cell as
This is the required edge length of the FCC structure of Delawarium
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