Defects occur along the length of cable at an average of 5 defects per 4,000 feet. ASsume that the probability of k defects in t feet of cable is given by the probability mass function: e -(5t/ 4000) (5 t/ 4,000 ) k P(k defects ) = . k! for k = 0, 1, 2, .. Find the probability that a 3,200 foot cable will have а. at most three defects b. at least four defects С. between 1 to 5 (inclusive) defects
Defects occur along the length of cable at an average of 5 defects per 4,000 feet. ASsume that the probability of k defects in t feet of cable is given by the probability mass function: e -(5t/ 4000) (5 t/ 4,000 ) k P(k defects ) = . k! for k = 0, 1, 2, .. Find the probability that a 3,200 foot cable will have а. at most three defects b. at least four defects С. between 1 to 5 (inclusive) defects
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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
Transcribed Image Text:Defects occur along the length of cable at an average of 5 defects per 4,000 feet. Assume that the probability of k defects in t feet of
cable is given by the probability mass function:
-( 5t/ 4000)
'(5t/4,000)k
e
P(k defects ) =
k!
for k = 0, 1, 2, .. Find the probability that a 3,200 foot cable will have
a.
at most three defects
b.
at least four defects
C.
between 1 to 5 (inclusive) defects
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