1. Find the value of fx (8√2) 2. Find the value of p₁ = P(64/9 ≤ x ≤ 12). 3. Find the probability p₂ = P(X ≥ 12). (f. (8/2) )-01178045370 3500
1. Find the value of fx (8√2) 2. Find the value of p₁ = P(64/9 ≤ x ≤ 12). 3. Find the probability p₂ = P(X ≥ 12). (f. (8/2) )-01178045370 3500
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![Let X be a random variable with cumulative distribution function
Fx (x)=0 if x ≤ 0,
Find the probability density function fx of X and
1. Find the value of fx (8√/2)
2. Find the value of p₁ = P(64/9 ≤ x ≤ 12).
3. Find the probability p₂ = P(X ≥ 12).
(fx (8√2), P₁, P2) = 0.1179,0.4537,0.2500
x
24
x²
192
1
if 0 < x≤ 8,
if 8 < x < 8√3,
if x > 8√3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1467f162-7185-45ab-925a-2589d3c8cce7%2F2157aec6-7100-47c5-97b7-36a4f3299be1%2Fxo53xf9_processed.png&w=3840&q=75)
Transcribed Image Text:Let X be a random variable with cumulative distribution function
Fx (x)=0 if x ≤ 0,
Find the probability density function fx of X and
1. Find the value of fx (8√/2)
2. Find the value of p₁ = P(64/9 ≤ x ≤ 12).
3. Find the probability p₂ = P(X ≥ 12).
(fx (8√2), P₁, P2) = 0.1179,0.4537,0.2500
x
24
x²
192
1
if 0 < x≤ 8,
if 8 < x < 8√3,
if x > 8√3.
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