def function(L, a): result = for i in range(len(L)-a+1): product for r in range(i, i+a): product *= L[r] result.append(product ** a) 1 !3D return result function([1.2, 3.4, 2.0], 3) => [543.3384960000001]
def function(L, a): result = for i in range(len(L)-a+1): product for r in range(i, i+a): product *= L[r] result.append(product ** a) 1 !3D return result function([1.2, 3.4, 2.0], 3) => [543.3384960000001]
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
change second for by if statement
![def function(L, a):
result =
for i in range(len(L)-a+1):
product
for r in range(i, i+a):
product *= L[r]
result.append(product ** a)
return result
1
=
function([1.2, 3.4, 2.0], 3) => [543.3384960000001]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19345655-0aa2-4ff9-ad9a-152a33b1de5e%2Fadc059bb-6a2a-458f-85fd-f78b5ba6575b%2F05s3qfo_processed.png&w=3840&q=75)
Transcribed Image Text:def function(L, a):
result =
for i in range(len(L)-a+1):
product
for r in range(i, i+a):
product *= L[r]
result.append(product ** a)
return result
1
=
function([1.2, 3.4, 2.0], 3) => [543.3384960000001]
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