Answered: def equate(x.y): return (x**y)/8 Which…

def equate(x.y): return (x**y)/8 Which of the following lines of code will output '512' in Python? equate(2, 64) equate(64, 2] equate(64, 2) equate[2, 64] NEXT BACK

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Use Python code with: "def recolorImage(img,color):" without using cv2 or PIL recolor(img, color) - Changes all non-white pixels of the image referred to by the parameter img to the specified color, and returns a new image with the changes. img is a 2D array of RGB pixels which represent images. color is a list containing 3 integers, each from 0 to 255, representing RGB values. To create a new image use the cmpt120image.getBlackImage() function which returns a new canvas to draw on.
Could you show me a different way to write this code in python? I’m trying to make the code simple and easy to understand
1. Divisors: In a class Divisors.java, read in a maximum integer n and use nested loops to print a list of divisors for each of 1 through n as shown in the following transcript. Sample transcript (input underlined): Largest integer? 100 1: 1 2: 1 2 3: 1 3 4: 1 2 4 95: 1 5 19 95 96: 1 2 3 4 6 8 12 16 24 32 48 96 97: 1 97 98: 1 2 7 14 49 98 99: 1 3 9 11 33 99 100: 1 2 4 5 10 20 25 50 100
Using c++ Contact list: Binary Search A contact list is a place where you can store a specific contact with other associated information such as a phone number, email address, birthday, etc. Write a program that first takes as input an integer N that represents the number of word pairs in the list to follow. Word pairs consist of a name and a phone number (both strings). That list is followed by a name, and your program should output the phone number associated with that name. Define and call the following function. The return value of FindContact is the index of the contact with the provided contact name. If the name is not found, the function should return -1 This function should use binary search. Modify the algorithm to output the count of how many comparisons using == with the contactName were performed during the search, before it returns the index (or -1). int FindContact(ContactInfo contacts[], int size, string contactName) Ex: If the input is: 3 Frank 867-5309 Joe…
def findOccurrences(s, ch): lst = [] for i in range(0, len(s)): if a==s[i]: lst.append(i) return lst Use the code above instead of enumerate in the code posted below. n=int(input("Number of rounds of Hangman to be played:")) for i in range(0,n): word = input("welcome!") guesses = '' turns = int(input("Enter the number of failed attempts allowed:")) def hangman(word): secrete_word = "-" * len(word) print(" the secrete word " + secrete_word) user_input = input("Guess a letter: ") if user_input in word: occurences = findOccurrences(word, user_input) for index in occurences: secrete_word = secrete_word[:index] + user_input + secrete_word[index + 1:] print(secrete_word) else: user_input = input("Sorry that letter was not found, please try again: ") def findOccurrences(s, ch): return [i for i, letter in enumerate(s) if letter == ch] *** enumerate not discussed in…
Hello, I have an assignment in the python program. Professor gives me a text like this: January.txt 217283921200.5619.18,29.15,78.75,212.10100,20,410.29 The first line is an account number, the second line is the beginning balance, the third line is withdrawn and the last line is deposits. How can I separate every single line to read them. Can I use the loop function? Below is the assignment direction. Thank you very much ___________________________________________________________ Complete the following program: a) Read in and store the data from the file called “January.txt”. This file includes the customer’s account number, beginning balance, withdrawals, and deposits. (In that order) Note: Make sure you look at the file before you begin the project! b) Prompt the user for his/her name and age. c) Convert the customer’s name to a username that consists of the first letter of the first name, the first 5 digits of last name, and the customer’s age.(All letters should be lowercase)…
This is a python file Fix this code and the output is the attachment #filename: modValidateEmail.py def isValidMSUMEmail(email): if email.count('@') != 1: return False tmp= email.split('@') if len(tmp) == 0: return False userName = tmp[0] if not userName[0].isalpha(): return False for c in userName: if not c.isalpha() and c != '.': return False inst= tmp[1] if inst != 'mnstate.edu': return False else: return True #filename: UnitTestValidEmail.py from unittest import * from modValidateEmail import * class TestValidEmail(TestCase): #create a subclass of unittest.TestCase def testUserName(self): self.assertEqual(isValidMSUMEmail('.joe@mnstate.edu'),False) self.assertEqual(isValidMSUMEmail('joe4@mnstate.edu'),False) self.assertEqual(isValidMSUMEmail('joe$smith@mnstate.edu'),False) self.assertEqual(isValidMSUMEmail('joe.smith@mnstate.edu'),True) def…
Can anyone help solving this problem In Python
in c++ please paste working code. the program should Input- Julia Lucas Mia -1 With an expected output of- Julia Lucas Mia Julia Mia Lucas Lucas Julia Mia Lucas Mia Julia Mia Julia Lucas Mia Lucas Julia
PYTHON/JUPYTER NOTEBOOKS Write a code to import the following reaction mechanism for nitric acid radiolysis attached,please keep the order of reactions the same, and display the reaction. # Nitric acid radiolysis (sample)*NO3^2- + H^+ <-> *NO2 + OH^-e^- + NO3^- <-> *NO3^2-*NO3^2- + H^+ <-> HNO3 + e^-*NO3^2- + *OH <-> NO3^- + OH^-*NO3^2- + O2 <-> NO3^- + O2^-N2O4 + H2O <-> NO3^- + NO2^- + 2 H^+*NO2 + *OH <-> NO3^- + H^+*NO2 + H* <-> HNO2*NO2 + HO2* <-> O2NO2HO2NO2H <-> O2NO2^- + H^+O2NO2^- + H^+ <-> O2NO2HO2NO2^- + H^+ + 2 e^- <-> OH^- + NO3^-O2NO2H + e^- <-> *OH + NO3^-NO2^- + *OH <-> *NO2 + OH^-NO2^- + e^- <-> NO2^2-NO2^- + H2O + e^- <-> NO + 2 OH^-ONO2H + e^- <-> *NO2 + OH^-NO + e^- <-> NO^-NO + H* <-> NO^- + H^+NO + *OH <-> NO2^- + H^+NO + O2^- <-> ONO2^-NO + HO2* <-> ONO2HONO2^- + e^- + H2O <-> *NO2 + 2 OH^-*NO2 + NO + H2O <-> 2 HNO2 b)…