def checkTriplet(array): n = len(array) for i in range(n): array[i] = array[i]**2 array.sort() for i in range(n - 1, 1, -1): s = set() for j in range(i - 1, -1, -1): if (array[i] - arra
def checkTriplet(array): n = len(array) for i in range(n): array[i] = array[i]**2 array.sort() for i in range(n - 1, 1, -1): s = set() for j in range(i - 1, -1, -1): if (array[i] - arra
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
def checkTriplet(array):
n = len(array)
for i in range(n):
array[i] = array[i]**2
array.sort()
for i in range(n - 1, 1, -1):
s = set()
for j in range(i - 1, -1, -1):
if (array[i] - array[j]) in s:
return True
s.add(array[j])
return False
arr = [3, 2, 4, 6, 5]
checkTriplet(arr)
# True.
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