Answered: ded: int j = ((i++) * (i++)); From this…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The Problem: Parameterized macros can cause unexpected things to happen. Consider the following case:
#define SQUARE(x) ((x) * (x))
int i = 5;
int j = SQUARE(i++);
What's the value of j? The answer is that it's compiler dependent. And the value of i is definitely not 6. Why? Just look at the code after the macro is expanded:
int j = ((i++) * (i++));
From this we can see that i is increment twice. Also since the order of the operations is not specified by the C++ standard, the actual value of j is compiler dependent.

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