**Determine the Validity of Proposed Lewis Structures**This educational exercise aims to evaluate the reasonableness of given Lewis structures. Each structure is analyzed based on the number of valence electrons and adherence to the octet rule.### Table OverviewThe table consists of columns for proposed Lewis structures and options to determine their validity. Each structure includes checkboxes to assess specific criteria.#### Proposed Lewis Structures:1. **Structure 1:** - **Molecule:** \( \text{H} - \overset{\cdots}{\text{C}} = \overset{\cdots}{\text{C}} - \text{H} \) 2. **Structure 2:** - **Ion:** \([ \overset{\cdots \cdots}{\text{C}} \equiv \overset{\cdots}{\text{N}} ]^{-}\)3. **Structure 3:** - **Ion:** \([ \text{H} - \overset{\cdots}{\text{C}} \equiv \overset{\cdots}{\text{C}} ]^{-}\)### Evaluation CriteriaFor each structure, choose from:- **Yes:** The structure is reasonable.- **No, it has the wrong number of valence electrons.** - Provide the correct number: [ ]- **No, it has the right number of valence electrons but doesn't satisfy the octet rule.** - List problematic atoms: [ ]### Instructional Note- For atoms failing the octet rule, repeat the element symbol as required. For example, if multiple oxygen atoms are problematic, enter "O,O".This task enhances understanding of chemical bonding and molecular geometry, reinforcing the accurate representation of electron configurations in molecules and ions.

Lewis Structure- If the compound's molecular formula is known, electron dot structures or Lewis dot formulas can be drawn. It describes the type of bond and the placement of the atoms within the molecule that are joined together. Lewis dot structures, also known as electron dot structures, are schematics that show the interatomic chemical bonds in a molecule. Additionally, they show how many lone pairs there are overall in each of the atoms that make up the molecule. Common names for Lewis dot structures include electron dot structures and Lewis structures. Lewis described an acid as an electron pair acceptor, while a base is an electron pair donor.Compound I- C2H2 The atomic number of C is 8 and its electronic configuration is 1s22s22p2 The number of valence electrons in the C = 4 The atomic number of H is 1and its electronic configuration is 1s1 The number of valence electrons in the H = 1 Total number of valence electrons =4×2+1×2 =10 But the given structure has the total valence electrons = 14 which is wrong. The correct choice from the option is- No, it has the wrong number of valence electrons The correct total number of valence electrons =4×2+1×2 =10 The symbols for the problem are - "C, C" The correct lewis structure is as follows,Compound II- CN- The atomic number of C is 6 and its electronic configuration is 1s22s22p2 The number of valence electrons in the C = 4 The atomic number of N is 7 and its electronic configuration is 1s22s22p3 The number of valence electrons in the N = 5 The number of valence electrons =4+5 =9 But it has one negative charge which means 1 electron will be added to the valence electrons. The total number of valence electrons =9+1 = 10 The given structure has the total valence electrons = 10 which is Correct but does not satisfy the octet rule. The correct choice from the option is- No, it has right number of valence shell but does not satisfy the octet rule. The symbols for the problem are - "C,N" The correct lewis structure is [:C≡N:]-Compound III - HC2- The atomic number of C is 6 and its electronic configuration is 1s22s22p2 The number of valence electrons in the C = 4 The atomic number of His 1 and its electronic configuration is 1s1 The number of valence electrons in the H = 1 The number of valence electrons =4×2+1 =9 But it has one negative charge which means 1 electron will be added to the valence electrons. The total number of valence electrons =9+1 = 10 The given structure has the total valence electrons = 10 which is Correct. The correct choice from the option is- Yes The HC2- ion has the correct number of valence electrons and the lewis structure is also correct.