Deafness in cocker spaniels is inherited. The allele for deafness (d) is recessive to the allele for hearing (D). Two cocker spaniels that are heterozygous for hearing are mated together. What is the chance that a puppy will be deaf? 0% O 25% 50% O 100%
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- When you decide to breed your Labrador retriever Molly and sell the puppies, you discover that two of Mollys four siblings have developed a hip disorder that is traceable to the action of a single recessive allele. Molly herself shows no sign of the disorder. If you breed Molly to a male Labrador that does not carry the recessive allele, can you assure a purchaser that the puppies will also be free of the condition? Explain your answer.Crossing Pea Plants: Mendels Study of Single Traits Wet ear wax (W) is dominant over dry ear wax (w). a. A 3 : 1 phenotypic ratio of F1 progeny indicates that the parents are of what genotype? b. A 1 : 1 phenotypic ratio of F1 progeny indicates that the parents are of what genotype?Crossing Pea Plants: Mendels Study of Single Traits Of the following, which are phenotypes and which are genotypes? a. Aa b. tall plants c. BB d. abnormal cell shape e. AaBb
- Redgreen color blindness is an X-linked recessive disorder in humans. Your friend is the daughter of a color-blind father. Her mother had normal color vision, but her maternal grandfather was color-blind. What is the probability that your friend is color-blind? (a) 1 (b) (c) (d) (e) 0Aboten te breed a pea plant that displays a very specific phenotype, they would like a pea plant with green seeds in a yellow pod Using their knowledge of the pea plants they are working with they have del hich trat e dominant and which are recessive, as well as, what alieles are present in the parent plants. Pea Plant Traits Flower Flower Seed Color Po S Pod Color Plant Sire Color Location Axial YG Yg yG yg Infiated Green Purple Tall yG R Y. G. T. yg Terminal Short (Dwarf) Weinkled Green Constricted Yellow White yG yg y t PreviousThe comb shape of chickens is an example of an interesting inheritance pattern. Two genes, each with a dominant and recessive allele, determine comb phenotypes as follows: Comb Shape Description Genotype Single Comb homozygous recessive for both r and p rrpp Walnut comb both dominant alleles are present; R and P alleles are present R_P_ Pea comb the dominant allele P is present and the dominant allele R is absent rrP_ Rose comb the dominant allele R is present and the dominant allele P is absent R_pp Which of the following represents the correct phenotypes of the F2 offspring? Select one: a. Phenotype Single Walnut Pea Rose 9/16 3/16 3/16 1/16 b. Phenotype Single Walnut Pea Rose 3/16 1/16 9/16 3/16 c. Phenotype Single Walnut Pea Rose 1/16 9/16 3/16 3/16 d. Phenotype Single Walnut Pea Rose 3/16 9/16 1/16 3/16
- The comb shape of chickens is an example of an interesting inheritance pattern. Two genes, each with a dominant and recessive allele, determine comb phenotypes as follows: Comb Shape Description Genotype Single Comb homozygous recessive for both r and p rrpp Walnut comb both dominant alleles are present; R and P alleles are present R_P_ Pea comb the dominant allele P is present and the dominant allele R is absent rrP_ Rose comb the dominant allele R is present and the dominant allele P is absent R_pp If the P1 generation is a rose comb (RRpp) crossed with a pea comb (rrPP), which of the following represents the correct genotype and phenotype of the F1 offspring? Select one: a. Genotype Phenotype RRPP Single comb b. Genotype Phenotype RrPp walnut comb c. Genotype Phenotype RrPp pea comb d. Genotype Phenotype RRPP walnut combD Page view A Read aloud Draw Highlight PRA Can you curl your tongue up on the sides? Tongue-curling in humans is a dominant genetic trait. Suppose a man who is Tt for tongue-curling marries a woman who is also Tt for this trait. What are the possible genotypes and phenotypes of their children and the percent chance for each? 4. 1 Fill in the table: Genotype Phenotype ChanceHomozygous mice are better able to adapt to their environment. O Heterozygous mice live shorter lives since they do not have the lethal allele. Is it possible to determine the genotype of an individual expressing a dominant phenotype? Provide evidence to support your claim * Provide at least 3 COMPLETE SENTENCES Your answer This is a required question Is it possible to determine the genotype of an individual expressing a recessive phenotype? Provide evidence to support your claim Provide at least 3 COMPLETE SENTENCES a phenotype is a personality's noticeable traits. Eye color, height and, evident. The genetic contribution to the constitution is named the genotype, So basically phenotypes are on the surfacel Yes it is possible
- n pea plants, the appearance of flowers along the main stem is a dominant phenotype called axial and is controlled by the T allele. The recessive phenotype, produced by the E t allele, has flowers only at the end of the stem and is called terminal. Seedpod form iS determined by a second gene. The dominant phenotype inflated is controlled by allele C, and a recessive constricted form, produced by allele c. A pure breeding axial, constricted plant is crossed to one that is pure-breeding terminal, inflated. A. The F1 progeny of this cross are allowed to self-fertilize. What is the expected distribution of phenotypic classes among the F2 progeny? -> TTcc t난 CC x Et 1:2:1n an example of recessive epistasis the deposition of pigment into hair follicles of the Labrador Retriever is governed by a dominant gene (C) and lack of deposition by its recessive allele (c). Lack of pigment deposition produces a yellow coat color. The color of pigment is governed by an independently assorting hypostatic gene, the dominant allele (B) produces black pigment and its recessive allele (b) produces brown. What coat color ratio is expected from the cross of a brown dog (bbCc) to a black dog (BbCc)? 1/2 brown, 1/2 black 1/4 black, 1/4 brown, 1/2 yellow 1/2 black, 1/4 brown, 1/4 yellow 3/8 black, 1/8 brown, 1/2 yellow 3/8 black, 3/8 brown, 1/4 yellowMendel's P1 Dihybrid Cross First parental (P1) generation WWGG wWgg Gametes WG Wg First filial (F1) generation Genotype Phenotype g bns es WwGg round and yellow- seeded plants Figure 1.3 Activity 4. SELF-CHECK 1. Based on the reșults of the dihybrid cross, can you tell which traits are dominant? Recessive? The P1 dihybrid cross is illustrated in Figure 1.3. Study it carefully. Capital letter W represents round pea seed which is dominant over wrinkled pea seed (w). Second parental (P2) generation (F1 self-pollinated) Ww Gg WwGg WG riWg WG of WG Gametes wG wG wg wg Second filial (F1) generation WG Wg wG to vitnsb Male wg Female WwGg 4 8 WWGg 2 wwgg 6 WwGg 10 14 WG WWGG 1 WWGG 3 Wg wG wWGg 5 WwGg 9 WwGg 13 WwGg 7 wwGg 11 wwGg 15 Wwgg wwGg 12 16 Wg Wwgg wwgg 2WwGg 4WwGg 2Wwgg Genotypic ratio 1 WWGG 2 WWG9 1WWgg 1wwGG 2wwGg 1wwgg