ReviewData taken from a stress-strain test for a ceramic aregiven in the table. The curve is linear between the originand the first point.No elements selecteda(ksi)50 +40 -30Figure1 of 12010 +o (ksi)€ (in./in.)ex 10(in./in.)0.51.01.52.02.533.20.000645.50.0010Press (ENTER) to select this element. Press ESC) to return to the main menu. Press CTRL+Q) to quit the application.49.40.001451.50.001853.40.0022

Given data: Stress=σ Strain=ε Need to draw the graph between the stress and strain.

Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. No elements selected o(ksi) 50 40 + 30 - Figure < 1 of 1 > 20 - 10 o (ksi) e (in./in.) ex 10(in./in.) 0.5 1.0 1.5 2.0 2.5 0.0006 0.0010 33.2 45.5 Press ENTER to select this element. Press ESC) to retum to the main menu. Press CTRL+Q to quit the application. 49.4 0.0014 51.5 0.0018 53.4 0.0022

Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. No elements selected o(ksi) 50 40 + 30 - Figure < 1 of 1 > 20 - 10 o (ksi) e (in./in.) ex 10(in./in.) 0.5 1.0 1.5 2.0 2.5 0.0006 0.0010 33.2 45.5 Press ENTER to select this element. Press ESC) to retum to the main menu. Press CTRL+Q to quit the application. 49.4 0.0014 51.5 0.0018 53.4 0.0022

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Review Data taken from a stress-strain test for a ceramic are No elements selected o(ksi) given in the table. The curve is linear between the origin and the first point. 50 40 30 Figure 1 of 1 20 10 σ (ksi) e (in./in.) ex 10-*(in./in.) 0.5 1.0 1.5 2.0 25 33.2 0.0006 45.5 0.0010 Press (ENTER to select this element. Press (ESc to return to the main menu. Press (CTRL+Q) to quit the application. 49.4 0.0014 51.5 0.0018 53.4 0.0022
Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Figure σ (ksi) 0 33.2 45.5 49.4 51.5 53.4 € (in./in.) 0 0.0006 0.0010 0.0014 0.0018 0.0022 < 1 of 1 Part A Plot the stress-strain diagram. (Figure 1) +SGA0 No elements selected σ(ksi) Submit Request Answer 50 40 30+ 20 10 0.5 1.0 1.5 2.0 2.5 €x 10-³(in./in.) ? Select the elements from the list and add them to the canvas setting the appropriate attributes. Press [CTRL+M) to get to the main menu.
figure five shows the tensile strength. The graph depicting stress (MPa) vs. stain ( percent ). The lines will appear at various PCL. Explain the length and why it does not continue and falls. If I'm not wrong, there was a tutorial question based on this.
Desuon T EHide blocks Determine the Young's modulus of a metal alloy having the following tensile stress-strain diagram. ot yet nswered Stress-Strain Diagram Marked out of 5.00 1200 P Flag question 1000 800 1000 500 800 600 400 400 200 0.005 0.01 0.015 002 0.025 0.03 0.05 0.1 0.15 Strain (mm/mm) 0.2 0.25 Select one: O E = 1000 Mpa O E= 250 Gpa OE = 120 Gpa E = 50 Gpa E = 200 Gpa Stress (Mpa)
Correct one
640 480 160 0.002 0,004 0.006 0.008 0.010 Strain (mm/mm) A tensile test specimen of Aluminum alloy having a gauge length of 280 mm was tested to fracture. Stress and strain data obtained during the test are shown in the attached Figure. **Answers are approximate - do your best to read the graph. Determine: (a) the modulus of elasticity in GPa (4sigs). Enter this value into D2L answer box. (b) the proportional limit in MPa (3sigs). (c) the ultimate strength in MPa (3sigs). (d) Ductility of material based on percent elongation. (3sigs) Your Answer: Stress (MPa)
Name: Surname: Student ID: ME 216 MECHANICS OF MATERIALS QUIZ #2 6) QUESTION σ (MPa) 25.03.2019 490 420 350 280 210 140 70 (mm/mm) 0 0.002 0.004 0.006 0.008 0.010 A tension test was performed on a 7075-T6 aluminum tensile test specimen. The results are given in the figure above. According to this data, find: a. Young modulus of the material, b. Yield stress of the material (be careful, there is no any sharp yield point), c. Modulus of the resilience, d. If the material is stressed up to 420 MPa stress, what is the permanent elongation remained in the material if its length is 90 mm. e. For a 20 mm diameter bar made up of from the same material, what is the maximum load that can be applied without plastic deformation. ANSWER E=A ٤ E = 70.106 σ = 70 MPa at ε=0,0009 = 77,776 Pa 0.0009
30. In a typical tension test a dog-bone shaped specimen is pulled in a machine. During the test, the force F needed to pull the specimen and the length L of a gauge section are measured. This data is used for plotting a stress-strain diagram of the material. Two definitions, engineering and true, exist for stress and strain. The engineering stress F de and strain e are defined by oe F %3D and A0 L-Lo where Lo and Ao are the initial gauge 6, = Lo length and the initial cross-sectional area of the specimen, respectively. The true stress o, and strain e are defined by o, 는는 and q %3D = In A0 Lo The following are measurements of force and gauge length from a ten- sion test with an aluminum specimen. The specimen has a round cross sec- tion with a radius of 0.25 in. (before the test). The initial gauge length is 0.5 in. Use the data to calculate and generate the engineering and true stress- strain curves, both on the same plot. Label the axes and use a legend to identify the curves. Units:…
a . Sketch stress strain curve if the result shown in table represent the force and extension happened in steel, and show Mechanical properties that we get from tensile test on curve? (10p)Note : Lo=80 mm , Do=10 mm , use excel to plot the curve ExtensionLoad(mm) (N)0 0.900.83 4694.341.67 4831.412.50 4781.083.33 4918.834.17 4926.585.00 5257.075.83 5437.016.66 5575.888.33 5775.189.16 5847.5210.83 5965.4111.67 6010.5312.50 6042.5713.33 6072.2614.16 6092.9315.00 6113.2416.67 6140.3617.50 6146.3718.33 6148.1419.16 6149.1725.00 5940.2125.83 5675.3326.67 4725.52b. What is meant by modulus of rigidity? if it increases what does happen to material? (2p)
In the graph, the module of toughness can be shown to be represented by: A) The area associated with necking B) The rectangular area label yielding C) The triangular area in the elastic region D) The sum of the entire shaded area under the curve
Show complete solution using the flexural stress formula.
Give correct solution otherwise skip.