Help. And the time for all is 2.95s Data Table 1: Mass of the ballMass of the ballData Table 2: Trajectory Points for Trial 5Point on Position (m)trajectory[height]Point 10.683Point 2Point 3Point 4Point 50.8180.8560.7990.651Point on Position (m)trajectory[height]Velocity(m/s)1.8060.869-0.0920.15-1.026-1.895Data Table 3: Trajectory Points for Trial 7Velocity(m/s)Trial 5PE (J)PE=mghTrial 7PE (J)PE=mghkgKE (J)KE=1/2mv²KE (J)KE=1/2mv²TE (J)TE PE+KETE (J)TE=PE+KE

Answered: Image /qna-images/answer/5d47bc17-ad50-4390-b0d1-1d5844573d18.jpg

Data Table 1: Mass of the ball Mass of the ball Data Table 2: Trajectory Points for Trial 5 Point on Position (m) [height] trajectory Point 1 0.683 Point 2 Point 3 Point 4 Point 5 0.818 Point on trajectory 0.856 0.799 0.651 Position (m) [height] Velocity (m/s) 1.806 0.869 -0.092 0.15 -1.026 -1.895 Data Table 3: Trajectory Points for Trial 7 Velocity (m/s) I Trial 5 PE (J) PE=mgh Trial 7 PE (J) PE=mgh kg KE (J) KE=1/2mv² KE (J) KE=1/2mv² TE (J) TE=PE+KE TE (J) TE-PE+KE

Data Table 1: Mass of the ball Mass of the ball Data Table 2: Trajectory Points for Trial 5 Point on Position (m) [height] trajectory Point 1 0.683 Point 2 Point 3 Point 4 Point 5 0.818 Point on trajectory 0.856 0.799 0.651 Position (m) [height] Velocity (m/s) 1.806 0.869 -0.092 0.15 -1.026 -1.895 Data Table 3: Trajectory Points for Trial 7 Velocity (m/s) I Trial 5 PE (J) PE=mgh Trial 7 PE (J) PE=mgh kg KE (J) KE=1/2mv² KE (J) KE=1/2mv² TE (J) TE=PE+KE TE (J) TE-PE+KE

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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