A parallel-plate capacitor has the capacitance of C₁ = 10 µF when the distance of the two plates is d = 18 cm. A battery with the emf = 8 V is used to charge the capacitor. How much charge can be put on the parallel-plate capacitor? (note that for micro, 106, you can use u for μ .) Number Units Correct response: 8E-5 C ± 5.0% Now, consider the following two cases separately: Case 1: if the emf stays connected, but the distance of the parallel plates is changed to d₂ = 6 cm. 2. What is the new capacitance C₂ and how much is the charge Q₂ in the capacitor? C₂ Number Units Correct response: 3E-5 F ± 5.0% Q₂ Number Units Correct response: 2.4E-4 C = 5.0% Case 2: After the initial charging, the emf is removed. Therefore, the amount of charge you calculated from the question #1 remains in the capacitor. Now, again, the distance of the parallel plates is changed to d₂ =6 cm. What is the potential difference V₂ across the capacitor? V₂ Number Units

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Can you explain how the answer is 2.66667 for the last problem?

A parallel-plate capacitor has the capacitance of C₂ = 10 µF when the distance of the two plates is d = 18 cm. A battery with the emf = 8
V is used to charge the capacitor.
How much charge can be put on the parallel-plate capacitor? (note that for micro, 106, you can use u for μ.)
Number
Units
Correct response: 8E-5 C ± 5.0%
Now, consider the following two cases separately:
Case 1: if the emf stays connected, but the distance of the parallel plates is changed to d₂ = 6 cm.
2. What is the new capacitance C₂ and how much is the charge Q₂ in the capacitor?
C₂ Number
Units
Correct response: 3E-5 F ± 5.0%
Q2 Number
Units
Correct response: 2.4E-4 C ± 5.0%
Case 2: After the initial charging, the emf is removed. Therefore, the amount of charge you calculated from the question #1 remains in
the capacitor. Now, again, the distance of the parallel plates is changed to d₂ =6 cm.
What is the potential difference V₂ across the capacitor?
V₂ Number
Units
Correct response: 2.666667 V ± 5.0%
Transcribed Image Text:A parallel-plate capacitor has the capacitance of C₂ = 10 µF when the distance of the two plates is d = 18 cm. A battery with the emf = 8 V is used to charge the capacitor. How much charge can be put on the parallel-plate capacitor? (note that for micro, 106, you can use u for μ.) Number Units Correct response: 8E-5 C ± 5.0% Now, consider the following two cases separately: Case 1: if the emf stays connected, but the distance of the parallel plates is changed to d₂ = 6 cm. 2. What is the new capacitance C₂ and how much is the charge Q₂ in the capacitor? C₂ Number Units Correct response: 3E-5 F ± 5.0% Q2 Number Units Correct response: 2.4E-4 C ± 5.0% Case 2: After the initial charging, the emf is removed. Therefore, the amount of charge you calculated from the question #1 remains in the capacitor. Now, again, the distance of the parallel plates is changed to d₂ =6 cm. What is the potential difference V₂ across the capacitor? V₂ Number Units Correct response: 2.666667 V ± 5.0%
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