Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![Absorbance
Stnd:
[Fe(SCN)2+]
Absorbance
0000
0.432
1.
000000'0
2.
060000'0
0.000106
0.480
0.000127
0.633
5.
0.000189
0.831
0.000204
0.887
Calibration Curve
000
y 4339.8x+0.0258
0.800
0.400
0200
0.000150
0.000200
(Fe(SCN)2+]
Absorbance Data Needed to Fill Row 3, Part 2
Experiment
Optical Absorbance
(Fe(SCN)2+]
0.290
1.
0.524
0.803
1.024
5
66
Original (SCN-
[Fe(SCN)2+] (Final) K
0.000063 148.6799
Original [Fe3+]
0.00165
0.00033
0.00165
0.0001135 135.1678
990000
0.000172 142.2659
0.00165
66000'0
0.0002223 141.8466
0.00165
ZETO0'O
0.0002596 134.2843
0.00165
0.00165](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb39a791-932a-40e9-8866-3329ef2f764e%2Fa4b2f63e-6d9a-4965-b033-543dc466133a%2Flolkxf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Absorbance
Stnd:
[Fe(SCN)2+]
Absorbance
0000
0.432
1.
000000'0
2.
060000'0
0.000106
0.480
0.000127
0.633
5.
0.000189
0.831
0.000204
0.887
Calibration Curve
000
y 4339.8x+0.0258
0.800
0.400
0200
0.000150
0.000200
(Fe(SCN)2+]
Absorbance Data Needed to Fill Row 3, Part 2
Experiment
Optical Absorbance
(Fe(SCN)2+]
0.290
1.
0.524
0.803
1.024
5
66
Original (SCN-
[Fe(SCN)2+] (Final) K
0.000063 148.6799
Original [Fe3+]
0.00165
0.00033
0.00165
0.0001135 135.1678
990000
0.000172 142.2659
0.00165
66000'0
0.0002223 141.8466
0.00165
ZETO0'O
0.0002596 134.2843
0.00165
0.00165
![(ISCN
Data Report Sheet: Spectrophotometric Determination of an Equilibrium
Constant.
Part A: Determination of a Calibration Curve;
Stnd.1
Std. 2
Stnd. 3
Stnd 4
Sind. 5
Stad. 6
(Но)
0.000090
0.000106 0.000127 0.000189 0.000204
(Fe(SCN)"]
Column A
0.432
0.480
0.633
0.831
0.887
Absorbance
Column E
0.
y= 4339.8x + 0.0258
Equafion of Calibration Line:
0.9904
Correlation Coefficient;
4339.8
Slope (br):
Part B: Determination of K
Expt. 1
Еxpt, 2
Expt. 3
Expt. 4
Expt. 5
0,00165
0.00165
0.00165
0.00165
000165
(Table 1)
0.00033
0.00066
0.00099
0.001
0.00165
ISCN at
(Table 1)
0.290
0.524
0.803
1.024
1.199
[Fe(SCN)*l
Column F
|Fe"leqt
148.6799
135.1678
142.2659
141 8466
134.2843
Average K:140 448
I](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb39a791-932a-40e9-8866-3329ef2f764e%2Fa4b2f63e-6d9a-4965-b033-543dc466133a%2Ffr7abzc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(ISCN
Data Report Sheet: Spectrophotometric Determination of an Equilibrium
Constant.
Part A: Determination of a Calibration Curve;
Stnd.1
Std. 2
Stnd. 3
Stnd 4
Sind. 5
Stad. 6
(Но)
0.000090
0.000106 0.000127 0.000189 0.000204
(Fe(SCN)"]
Column A
0.432
0.480
0.633
0.831
0.887
Absorbance
Column E
0.
y= 4339.8x + 0.0258
Equafion of Calibration Line:
0.9904
Correlation Coefficient;
4339.8
Slope (br):
Part B: Determination of K
Expt. 1
Еxpt, 2
Expt. 3
Expt. 4
Expt. 5
0,00165
0.00165
0.00165
0.00165
000165
(Table 1)
0.00033
0.00066
0.00099
0.001
0.00165
ISCN at
(Table 1)
0.290
0.524
0.803
1.024
1.199
[Fe(SCN)*l
Column F
|Fe"leqt
148.6799
135.1678
142.2659
141 8466
134.2843
Average K:140 448
I
Expert Solution
Experiment 1
Equation obtained from calibration curve is-
y = 4339.8x + 0.0258
y = Absorbance
x = [FeSCN2+]
For y = 0.290
0.290 = 4339.8x + 0.0258
x = 0.000061
| [Fe3+] | [SCN-] | [FeSCN2+] | |
| Initial | 0.00165 | 0.00033 | 0 |
| Change | -x | -x | +x |
| Equilibrium | 0.00165-x | 0.00033-x | x |
Now,
[FeSCN2+]eq = x = 0.000061
So,
[Fe3+]eq = (0.00165 - 0.000061)
= 0.001589
[SCN-]eq = (0.00033-0.000061)
= 0.000269
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