Data from the latest census show that households in Oaktown have 0 to 5 children. Suppose that a household in Oaktown is randomly selected. Let X be the number of children living in that household. Here is the probability distribution of X. 0 1 2 3 4 5 Value x of X P(X=x) For parts (a) and (b) below, find the probability that the randomly selected household has the number of children described. (a) No more than 1:0 (b) Greater than 3: 0.18 0.25 0.28 0.16 0.08 0.05 X 5
Data from the latest census show that households in Oaktown have 0 to 5 children. Suppose that a household in Oaktown is randomly selected. Let X be the number of children living in that household. Here is the probability distribution of X. 0 1 2 3 4 5 Value x of X P(X=x) For parts (a) and (b) below, find the probability that the randomly selected household has the number of children described. (a) No more than 1:0 (b) Greater than 3: 0.18 0.25 0.28 0.16 0.08 0.05 X 5
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Transcribed Image Text:Data from the latest census show that households in Oaktown have 0 to 5 children. Suppose that a household in Oaktown is randomly selected. Let X be the
number of children living in that household. Here is the probability distribution of X.
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Value x of X
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P(X=x)
0.18 0.25 0.28 0.16 0.08 0.05
For parts (a) and (b) below, find the probability that the randomly selected household has the number of children described.
(a) No more than 1:
(b) Greater than 3:0
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Step 1
For the probability distribution of the "no. of children in a household in the specified place:" (defined by the variable ) is given as:
Value of ; | 0 | 1 | 2 | 3 | 4 | 5 |
0.18 | 0.25 | 0.28 | 0.16 | 0.08 | 0.05 |
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